📄 formula.repository
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\form#0:$P(x)$\form#1:${a_0}+{a_1}x+{a_2}x^2+{a_3}x^3$\form#2:$[a_0, a_1, a_2, a_3]$\form#3:$a_0$\form#4:$r=p+q$\form#5:$p\leftarrow p+q$\form#6:$p+q$\form#7:$r=p-q$\form#8:$p-q$\form#9:$p\leftarrow p-q$\form#10:\[q=\frac{u}{v}\]\form#11:\[r=u\%v\]\form#12:$q=\frac{u}{v}$\form#13:$r=u\%v$\form#14:\[u\leftarrow \frac{u}{v}\]\form#15:$\frac{u}{v}$\form#16:$r(x)=s.p(x)$\form#17:$p(x)\leftarrow s.p(x)$\form#18:$s.p(x)$\form#19:$r=pq$\form#20:$y = p(x)$\form#21:$p(x)$\form#22:$\frac{p(x)}{(x - a)}$\form#23:$p(a)$\form#24:$q(x)=\frac{p(x)-p(a)}{(x - a)}$\form#25:$p(x)=q(x)(x - a)+p(a)$\form#26:$a$\form#27:$p(a)=0$\form#28:$q(x)$\form#29:$dy=p'(x)$\form#30:$p'(x)$\form#31:$p''(x)$\form#32:$q(z)=\frac{p(z)}{z-x}$\form#33:\[p(x)=a_0+a_1{x}+a_2{x^2}+...+a_n{x^n}\]\form#34:\[q(x)=|a_0|+|a_1|{x}+|a_2|{x^2}+...+|a_n|{x^n}\]\form#35:$p$\form#36:$a_1..a_n$\form#37:$q(x)=x^{n}p(x)$\form#38:$\frac{p(x)}{x^{-n}}$\form#39:$x^n$\form#40:$p\leftarrow pq$\form#41:$p(x)\leftarrow \frac{p(x)}{s}$\form#42:$r(x)=\frac{p(x)}{s}$\form#43:$p(z)$\form#44:$|p(z)|$\form#45:$x$\form#46:\[p(x)=-|a_0|+|a_1|x+|a_2|x^2+...+|a_n|x^n\]\form#47:$(a_0,a_1,a_2,...,a_n)$\form#48:$C_u$\form#49:\[C_u=1+max_n(|a_0|,|a_1|,...,|a_n|)\]\form#50:$G$\form#51:\[G_p=\left[\frac{|a_0|}{|a_n|}\right]^{\frac{1}{n}}, p(x)=a_0+a_1{x}+a_2{x^2}+...+a_n{x^n}, a_n\neq 0\]\form#52:$p(x)=ax+b$\form#53:$-\frac{b}{a}$\form#54:$p(x)=ax^2+bx+c$\form#55:\[S=b+\sqrt{b^2-4ac}\]\form#56:\[D=b-\sqrt{b^2-4ac}\]\form#57:\[q=\left\{ \begin{array}{ll} -S & \mbox{if} \left| S\right| >\left| D\right| \\ -D & \mbox{otherwise}\end{array}\right. \]\form#58:\[z_1=\frac{2c}{q}\]\form#59:\[z_2=\frac{q}{2a}\]\form#60:$1+\mbox{ETA}>1$
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