card.cpp.txt

用面相对象的思想

#include "card.h"
int main()
{
	Linkcard *InitLink=new Linkcard;InitLink->next=NULL;
	card Gamble(InitLink);
	int number;
	int ran;
		int o=1; 
			int u=1;
			int e=1;
	string J="John",T="Tony",P="Palmer";
	Linkcard *Linkfirst,*Linksecond,*Linkthird;
loop:	 cout<<"扑克牌游戏：金花"<<endl;
     cout<<"          .............................................."<<endl;
     cout<<"                     1.参与赌局的玩家                         "<<endl;
	 cout<<"                     2.一副崭新的完整的扑克牌                 "<<endl;
     cout<<"                     3.洗牌                                   "<<endl;
     cout<<"                     4.发牌，赌局开始                         "<<endl;
	 cout<<"                     5.获胜玩家                               "<<endl;
	 cout<<"                     6.exit"                                 ""<<endl;
     cout<<"          .............................................."<<endl;
     cout<<"Make a choice:";
     cin>>number;
	 while(number<1 || number>6)
	 {
		 cout<<"Error.操作错误!"<<endl;
		 cout<<"Make a new Choice:";
		 cin>>number;
	 }
	 switch(number)
	 {
	 case 1:
			 Gamble.Namecard(J,T,P);
			 cout<<"参与赌局的玩家:";
			 cout<<Gamble.Playerp()<<" ";
			 cout<<Gamble.PlayerR()<<" ";
			 cout<<Gamble.PlayerT()<<" ";
			 cout<<endl;
			 cout<<endl;
			 cout<<endl;
			 goto loop;
	 case 2:
			//Gamble.card(InitLink);
		 cout<<"一副完整的扑克牌："<<endl;
			Linkfirst=Gamble.Showcard();    //Linkfirst;
			Linksecond=Gamble.Outprintcard(Linkfirst); //Linksecond;
				cout<<endl;
				cout<<endl;
				cout<<endl;
		    goto loop;
	 case 3:
			Linkthird=Gamble.Shufflecard(Linksecond);
			Gamble.OutPrintcard(Linkthird);
			cout<<endl;
				cout<<endl;
				cout<<endl;
			goto loop;
	 case 4:
			ran=rand()%52;
			while(ran==1)
				ran=rand()%52;
			cout<<"得到三个人的牌："<<endl; 
			Gamble.Licesecard(Linkthird,ran);
			cout<<endl;
			cout<<endl;
				cout<<endl;
				cout<<endl;
			goto loop;
	 case 5:
		 Linkcard* Win;
		 Win=Gamble.Wincard(Gamble.headrJ,Gamble.headrT);
		 Gamble.Woncard(Win,Gamble.headrP);
		 cout<<endl;
		 cout<<endl;
		 cout<<endl;
		 goto loop;
		case 6:
			exit(0);
			cout<<endl;
			goto loop;              
	 }
			return(0);
}