paramcall.java

来自「Vodafone betavine java api source code, 」· Java 代码 · 共 60 行

package com.bv.api;

import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.Properties;

import sun.misc.BASE64Encoder;

/**
 * An APICall subtype that pases data to the server as parameters in the URL.
 * @author C. Oattes
 */
public abstract class ParamCall extends APICall {
	
	protected ParamCall() {
		super();
	}
	
	protected String connect(String uaid, String serverURL) throws ParamNotPresentException, InvalidParameterException, MalformedURLException, IOException {
		HttpURLConnection connection;
		BufferedReader responseReader; 
		URL connectionURL = null;
		checkParams(uaid);
		
		connectionURL = constructURL(uaid, serverURL);
		connection = (HttpURLConnection) connectionURL.openConnection();
		String username = "";
		String password = "";
		Properties values = new Properties();
		try {
			FileInputStream is = new FileInputStream("values.properties");
			values.load(is);
			username = values.getProperty("username");
			password = values.getProperty("password");
			String encoding = new BASE64Encoder().encode((username + ":" + password).getBytes());
			connection.setRequestProperty ("Authorization", "Basic " + encoding);
		} catch(IOException ioe) {
		    //Ignore if values.properties not present
		}
		
		connection.setConnectTimeout(5000);
		connection.connect();
		responseReader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
		//Read the response from the server - should be only 1 line
		String serverResponse = "";
		while(responseReader.ready()) {
			serverResponse += responseReader.readLine() + "\n" ;
		}
		connection.disconnect();
		System.out.println("Server response: " + serverResponse);
		return serverResponse;

	}
}