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      <P align=center><FONT color=blue size=5>Perfect Cubes</FONT> <BR>Time 
      Limit:1000MS&nbsp; Memory Limit:10000K<BR>Total Submit:1786 Accepted:1080 
      </P>
      <P><FONT color=blue size=5>Description</FONT><BR><FONT 
      face="Times New Roman" size=3>For hundreds of years Fermat's Last Theorem, 
      which stated simply that for n &gt; 2 there exist no integers a, b, c &gt; 
      1 such that a^n = b^n + c^n, has remained elusively unproven. (A recent 
      proof is believed to be correct, though it is still undergoing scrutiny.) 
      It is possible, however, to find integers greater than 1 that satisfy the 
      "perfect cube" equation a^3 = b^3 + c^3 + d^3 (e.g. a quick calculation 
      will show that the equation 12^3 = 6^3 + 8^3 + 10^3 is indeed true). This 
      problem requires that you write a program to find all sets of numbers 
      {a,b,c,d} which satisfy this equation for a &lt;= N.</FONT></P>
      <P><FONT color=blue size=5>Input</FONT><BR><FONT face="Times New Roman" 
      size=3>One integer N (N &lt;= 100).</FONT></P>
      <P><FONT color=blue size=5>Output</FONT><BR><FONT face="Times New Roman" 
      size=3>The output should be listed as shown below, one perfect cube per 
      line, in non-decreasing order of a (i.e. the lines should be sorted by 
      their a values). The values of b, c, and d should also be listed in 
      non-decreasing order on the line itself. There do exist several values of 
      a which can be produced from multiple distinct sets of b, c, and d 
      triples. In these cases, the triples with the smaller b values should be 
      listed first. </FONT></P>
      <P><FONT color=blue size=5>Sample Input</FONT><BR><FONT 
      face="Times New Roman" size=3><PRE>24</PRE></FONT>
      <P></P>
      <P><FONT color=blue size=5>Sample Output</FONT><BR><FONT 
      face="Times New Roman" size=3><PRE>Cube = 6, Triple = (3,4,5)
Cube = 12, Triple = (6,8,10)
Cube = 18, Triple = (2,12,16)
Cube = 18, Triple = (9,12,15)
Cube = 19, Triple = (3,10,18)
Cube = 20, Triple = (7,14,17)
Cube = 24, Triple = (12,16,20)</PRE></FONT>
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      <P><FONT color=blue size=5>Source</FONT><BR><FONT face="Times New Roman" 
      size=3><A 
      href="http://poj.grids.cn/searchproblem?field=source&amp;key=Mid-Central USA 1995">Mid-Central 
      USA 1995</A></FONT></P></TD></TR></TBODY></TABLE><FONT color=#333399 size=3>
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