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📄 14bsl2.c

📁 常用数值算法程序集
💻 C
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  #include "math.h"
  #include "14bsl1.c"
  double bsl2(n,x)
  int n;
  double x;
  { int i;
    double y,z,p,q,s,b0,b1;
    static double a[6]={ -2.957821389e+9,7.062834065e+9,
             -5.123598036e+8,1.087988129e+7,-8.632792757e+4,
             2.284622733e+2};
    static double b[6]={ 4.0076544269e+10,7.452499648e+8,
           7.189466438e+6,4.74472647e+4,2.261030244e+2,1.0};
    static double c[6]={ -4.900604943e+12,1.27527439e+12,
            -5.153438139e+10,7.349264551e+8,-4.237922726e+6,
             8.511937935e+3};
    static double d[7]={ 2.49958057e+13,4.244419664e+11,
            3.733650367e+9,2.245904002e+7,1.02042605e+5,
            3.549632885e+2,1.0};
    static double e[5]={ 1.0,-0.1098628627e-02,
             0.2734510407e-04,-0.2073370639e-05,
             0.2093887211e-06};
    static double f[5]={ -0.1562499995e-01,
             0.1430488765e-03,-0.6911147651e-05,
             0.7621095161e-06,-0.934935152e-07};
    static double g[5]={ 1.0,0.183105e-02,
             -0.3516396496e-04,0.2457520174e-05,
             -0.240337019e-06};
    static double h[5]={ 0.4687499995e-01,
             -0.2002690873e-03,0.8449199096e-05,
             -0.88228987e-06,0.105787412e-06};
    if (n<0) n=-n;
    if (x<0.0) x=-x;
    if (x==0.0) return(-1.0e+70);
    if (n!=1)
      { if (x<8.0)
          { y=x*x; p=a[5]; q=b[5];
	    for (i=4; i>=0; i--)
              { p=p*y+a[i]; q=q*y+b[i];}
            p=p/q+0.636619772*bsl1(0,x)*log(x);
          }
        else
          { z=8.0/x; y=z*z;
            p=e[4]; q=f[4];
            for (i=3; i>=0; i--)
              { p=p*y+e[i]; q=q*y+f[i];}
            s=x-0.785398164;
            p=p*sin(s)+z*q*cos(s);
            p=p*sqrt(0.636619772/x);
          }
      }
    if (n==0) return(p);
    b0=p;
    if (x<8.0)
      { y=x*x; p=c[5]; q=d[6];
        for (i=4; i>=0; i--)
          { p=p*y+c[i]; q=q*y+d[i+1];}
        q=q*y+d[0];
        p=x*p/q+0.636619772*(bsl1(1,x)*log(x)-1.0/x);;
      }
    else
      { z=8.0/x; y=z*z;
        p=g[4]; q=h[4];
        for (i=3; i>=0; i--)
          { p=p*y+g[i]; q=q*y+h[i];}
        s=x-2.356194491;
        p=p*sin(s)+z*q*cos(s);
        p=p*sqrt(0.636619772/x);
      }
    if (n==1) return(p);
    b1=p;
    s=2.0/x;
    for (i=1; i<=n-1; i++)
      { p=s*i*b1-b0; b0=b1; b1=p;}
    return(p);
  }

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