复件2 operater.txt

学生系统

#include "operater.h"

void Operater::display()
{
	cout<<endl<<endl;
	cout<<"--------------------------职工考勤管理-----------------------------"<<endl;
	cout<<"1:			添加一个职工信息"<<endl;
	cout<<"2:			删除一个职工信息"<<endl;
	cout<<"3:			显示所有职工的姓名"<<endl;
	cout<<"4:			根据姓名显示单个职工所有信息"<<endl;
	cout<<"5:			根据姓名对单个职工进行编辑"<<endl;
	cout<<"6:			帮助菜单"<<endl;
	cout<<"7:			保存数据"<<endl;
	cout<<"0:			退出系统"<<endl;
	cout<<"-------------------------------------------------------------------"<<endl;
}

void Operater::Loop()
{
	List L1;        //List 对象
	char ch[20];
	nodetype *p, *head;   
	int i;		    //存放节点序号

	p=L1.load();	//初始化：从外部读入数据创建链表

	head=p;
	display();

	while(1)
	{
		cout<<endl<<endl;
		cout<<"请输入选择（帮助选项--> 6 ）: "<<endl;
		cin>>ch;

		system("cls");
		if(L1.check(ch, "1"))
		{
			p=L1.insnode(0);
			head=p;

			system("cls");
			cout<<endl;
			cout<<"------------------添加一个职工信息-------------"<<endl;
			cout<<"下面输入个人信息: "<<endl;
			L1.editworker(p);
			
		}

		if(L1.check(ch, "2"))
		{
			system("cls");
			cout<<endl;
			cout<<"------------------删除一个职工信息------------"<<endl;
			L1.dispname();
			cout<<"请输入职工姓名: "<<endl;
			cin>>ch;
			i=L1.find2(ch);
			L1.delnode(i);
		}

		if(L1.check(ch, "3"))
		{
			system("cls");
			cout<<endl;
			cout<<"---------------显示所有职工名字---------------"<<endl;
			L1.dispname();
		}

		if(L1.check(ch, "4"))
		{
			system("cls");
			cout<<endl;
			cout<<"--------------根据姓名显示单个职工所有信息 --------------"<<endl;
			L1.dispname();
			cout<<"请输入职工姓名: "<<endl;
			cin>>ch;
			p=L1.find(ch);
			L1.dispnode(p);
		}

		if(L1.check(ch, "6"))
		{
			display();
		}

		if(L1.check(ch, "7"))		//保存数据
		{
			FILE *fp;
			if((fp=fopen("student.txt", "w"))==NULL)          
			{
				cout<<"打开文件失败"<<endl;
				return;
			}

			int i;
			char t[255];

			//将 L1.listlen() 赋予字符串中的数字
                    sprintf(t, "The Length Of Link: %d\n", L1.listlen()) ;\\把整数L1.listlen() 打印成一个字符串保存在t 中。

			fputs(t, fp);                    \\打印“the length of link：L1.listlen”覆盖原来的
			strcpy(t, "\n");
			fputs(t, fp);                         \\打印空格行

			p=L1.findnode(1);				//将链表头指针赋予 p

			for(i=0; i<L1.listlen(); i++)
			{
				
		          fputs(p->someone.name, fp);
		          fputs(p->someone.sex, fp);
		          fputs(p->someone.num, fp);
		          fputs(p->someone.birthday, fp);
		          fputs(p->someone.partment, fp);
		          fputs(p->someone.workyear, fp);
		          fputs(p->someone.E-mail, fp);
		          fputs(p->someone.telphone, fp);
		          fputs(p->someone.graduate, fp);
		          fputs(p->someone.address, fp);
		          fputs(p->someone.duty, fp);
		          fputs(p->someone.notice, fp);
	                  fputs(p->someone.in_time, fp);
	
				fputs(t, fp);

				p=p->next;
			}
			p=head;
			fclose(fp);
		}

		if(L1.check(ch, "5"))
		{
			char c[20];
			system("cls");
			cout<<endl;
			cout<<"------------------根据姓名对单个员工进行编辑 --------------"<<endl;
			L1.dispname();
			cout<<"请输入员工姓名: "<<endl;
			cin>>c;
			p=L1.find(c);

			system("cls");
			cout<<endl<<endl;
			cout<<"------------------------------------------------------------"<<endl;
			cout<<"1:			编辑个人信息"<<endl;
	                cout<<"2:			显示个人信息"<<endl;
			cout<<"3:			显示该员工所有信息"<<endl;
			cout<<"4:			帮助菜单"<<endl;
			cout<<"5:			返回上一级菜单"<<endl;
			cout<<"------------------------------------------------------------"<<endl;

			while(1)
			{
				cout<<endl<<endl;
				cout<<"请输入选择（帮助选项--> 8 ）: "<<endl;
				cin>>c;
				system("cls");

				if(L1.check(c, "1"))
				{
					system("cls");
					cout<<endl;
					cout<<"---------------------编辑个人信息 ----------------"<<endl;
					L1.editperson(p);
				}
			
		
			
				else if(L1.check(c, "2"))
				{
					system("cls");
					cout<<endl;
					cout<<"------------------显示个人信息 ------------------"<<endl;
					L1.dispworker(p);
				}


				else if(L1.check(c, "3"))
				{
					system("cls");
					L1.dispnode(p);
				}

				else if(L1.check(c, "4"))
				{
					system("cls");
					L1.help();
				}

				else if(L1.check(c, "5"))
				{
					display();
					break;	//用 break 跳出本循环，不要用 return ，return 是退出程序
				}
			}
		}

		else if(L1.check(ch, "0"))
			return;
	}
	return;
}