1347.txt

来自「自己AC的zju_acm上的若干个题目,都是自己辛辛苦苦AC的。」· 文本 代码 · 共 55 行

#include <iostream.h> 
#include <stdio.h> 

int main () { 
	long i,t; 
	long n,k,a1,a2,p1,p2,l,m; 
	double p,r,s,r1,r2; 

	cin>>t; 
	for (i=1;i<=t;i++) 
	{ 
		cin>>n>>p>>m>>r>>s; 
		p+=0.00000000000001; 
		r-=0.00000000000001; 
		l=n/m; 
		k=(p*n+s*m+p*m)/(2*p*m); 
		if (k>l) 
		k=l; 
		p1=p>0.0099? (k+1)*p*100-1 : (k+1)*p*100; 
		a1=n-(long)((double)p1/100/(p-0.00000000000002))*m; 
		r1=((double)p1/100-s)*a1-r; 
		k--; 
		if (k<0) 
			k=0; 
		p2=p>0.0099? (k+1)*p*100-1 : (k+1)*p*100; 
		a2=n-(long)((double)p2/100/(p-0.00000000000002))*m; 
		r2=((double)p2/100-s)*a2-r; 
		if (r2>r1)
		 { 
			p1=p2; 
			a1=a2; 
			r1=r2; 
		} 
		k+=2; 
		if (k>l) 
			k=l; 
		p2=p>0.0099? (k+1)*p*100-1 : (k+1)*p*100; 
		a2=n-(long)((double)p2/100/(p-0.00000000000002))*m; 
		r2=((double)p2/100-s)*a2-r; 
		if (r2>r1) 
		{ 
			p1=p2; 
			a1=a2; 
			r1=r2; 
		} 
		printf("price = %0.2f\n",(double)p1/100); 
		printf("audiences = %ld\n",a1); 
		printf("revenue = %0.2f\n",r1); 
		if (i!=t) 
		cout<<endl; 
		} 

	return 0; 
}