1.asm

里面有六个汇编程序

code   segment
       assume cs:code
start: mov cx,10
       mov bx,cx
       mov dl,30H
lop1:  mov ah,2
       int 21h
       inc dl
       loop lop1
       mov dl,0ah
       mov ah,2
       int 21h
       mov dl,0dh
       mov ah,2
       int 21h
       mov dl,30H
       mov cx,10  
       dec bx
       cmp bx,0
       jg lop1    ;ja与jg都行！
       mov ax,4c00h
       int 21h 
code   ends
end    start