📄 cimedium.html
字号:
<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" ><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" ><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" ><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" ><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" ><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" ><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" ><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" ><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" ><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" ><strong>Areas</strong></a></TR><br><TR><a href="volume.html"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" ><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" ><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" ><strong>Clocks</strong></a></TR><br><TR><a href="" ><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" ><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" ><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" ><strong>Puzzles</strong></a></TR></table></TD><TD valign="top"><a href="CI.html" target="right"><strong>BACK</strong></a><br><br><font size="5"><center><b><u>MEDIUM PROBLEMS</u></b></center></font><br><br><font size="4">1.The difference between C.I and S.I. on a certain sum at 10% per annum <br>for 2 yrs is Rs.631.find the sum<br>Sol:<br> MethodI:<br> NOTE:<br> a) For 2 yrs -------->sum=(1002D/R2)<br> b) For 3 yrs -------->sum=(1003D/R2(300+R))<br> Sum=1002*631/102 <br> =Rs.63100<br> MethodII:<br> Let the sum be Rs.X,Then <br> C.I.=X[1+(10/100)]2-X<br> S.I=(X*10*2)/100<br> =X/5<br> C.I-S.I.=21X/100-X/5<br> =X/100<br> X/100=631<br> X=Rs.63100<br><br><br>2.If C.I on a certain sum for 2 yrs at 12% per annum is Rs.1590.<br>What would be S.I?<br>sol:<br> C.I.=Amount-Principle<br> Let P be X<br> C.I=X[1+(12/100)]2-X<br> =>784X/625-X=1590<br> =>X=Rs.6250<br> S.I=(6250*12*2)/100=Rs.1500<br><br><br>3.A sum of money amounts to Rs.6690 after 3 yrs and to Rs.10035b<br> after 6 yrs on C.I .find the sum<br>sol:<br> For 3 yrs,<br> Amount=P[1+(R/100)]3=6690-----------------------(1)<br> For 6 yrs,<br> Amount=P[1+(R/100)]6=10035----------------------(2)<br> (1)/(2)------------[1+(R/100)]3=10035/6690<br> =3/2<br> [1+(R/100)]3=3/2-----------------(3)<br> substitue (3) in (1)<br> p*(3/2)=6690<br> =>p=Rs.4460<br> sum=Rs.4460<br><br><br>4.A sum of money doubles itself at C.I in 15yrs.In how many yrs will it <br>become 8 times?<br>sol: <br> Compound Interest for 15yrs p[1+(R/100)]15 <br> p[1+(R/100)]15=2P<br> =>p[1+(R/100)]n=8P<br> =>[1+(R/100)]n=8<br> =>[1+(R/100)]n=23<br> =>[1+(R/100)]n=[1+(R/100)]15*3<br> since [1+(R/100)] =2<br> n=45yrs<br><br><br>5.The amount of Rs.7500 at C.I at 4% per annum for 2yrs is<br>sol:<br> Iyear------------------7500+300(300------Interest on 7500)<br> IIyear ----------------7500+300+12(12------------4% interest on 300)<br> Amount=7500+300+300+12<br> =Rs.8112<br><br><br>6.The difference between C.I and S.I on a sum of money for 2 yrs at<br> 121/2% per annum is Rs.150.the sum is<br>sol:<br> Sum=1002D/R2=( 1002*150) /(25/2)2=Rs.9600<br><br><br>7.If the S.I on sum of money at 15% per annum for 3yrs is Rs.1200,<br>the C.I on the same sum for the same period at same rate is---------<br>sol:<br> S.I=1200<br> P*T*R/100=1200<br> P*3*5/100=1200<br> =>P=Rs.8000<br>C.I for Rs.8000 at 5% for 3 yrs is-------------8000+400<br> -------------8000+400+20<br> -------------8000+400+20+20+1<br> C.I =400+400+20+400+20+20+1<br> =Rs.1261<br><br><br><font size="3"><br><a href="CI.html" target="right"><strong>BACK</strong></a></font></font></TD></TR></table></html>⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -