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<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" ><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" ><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" ><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" ><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" ><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" ><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" ><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" ><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" ><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" ><strong>Areas</strong></a></TR><br><TR><a href="volume.html"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" ><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" ><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" ><strong>Clocks</strong></a></TR><br><TR><a href="" ><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" ><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" ><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" ><strong>Puzzles</strong></a></TR></table></TD><TD valign="top"><a href="simple.html" target="right"><strong>BACK</strong></a><br><br><font size="5"><center><b><u>COMPLEX PROBLEMS</u></b></center></font><font size="4"><pre>1. A certain sum of money amounts t 1680 in 3yrs & it becomes 1920 in 7 yrs .What is the sum. Sol:- 3 yrs - - - - - - - - - - - - - 1680 7 yrs - - - - - - - - - - - - - 1920 then, 4 yrs - - - - - - - - - - - - - 240 1 yr - - - - - - - - - - - - - ? (1/4) * 240 = 60 S.I in 3 yrs = 3*60 = 18012 Sum = Amount - S.I = 1680 - 180 = 1500 we get the same amount if we take S.I in 7 yrs I.e., 7*60 =420 Sum = Amount - S.I = 1920 - 420 = 1500 2. A Person takes a loan of Rs 200 at 5% simple Interest. He returns Rs.100 at the end of 1 yr. In order to clear his dues at the end of 2yrs ,he would pay: Sol:- Amount to be paid = Rs(100 + (200*5*1)/100 + (100*5*1)/100) = Rs 115 3. A Man borrowed Rs 24000 from two money lenders.For one loan, he paid 15% per annum and for other 18% per annum .At the end of one year,he paid Rs.4050.How much did he borrowed at each rate? Sol:- Let the Sum at 15% be Rs.x & then at 18% be Rs (24000-x) P1 = x R1 = 15 P2 = (24000-x) R2 = 18 At the end of ine year T = 1 (P1*T*R1)/100 + (P2*T*R2)/100 = 4050 (x*1*15)/100 + ((24000-x)*1*18)/100 = 4050 15x + 432000 - 18x = 405000 x = 9000 Money borrowed at 15% = 9000 Money borrowed at 18% = (24000 - 9000) = 15000 4. What annual instalment will discharge a debt of Rs. 1092 due in 3 years at 12% Simple Interest ? Sol:- Let each instalment be Rs x (x + (x * 12 * 1)/100) + (x + (x * 12 * 2)/100) + x = 1092 28x/25 + 31x/25 + x =1092 (28x +31x + 25x) = (1092 * 25) 84x = 1092 * 25 x = (1092*25)/84 = 325 Each instalement = 325 5. If x,y,z are three sums of money such that y is the simple interest on x,z is the simple interest on y for the same time and at the same rate of interest ,then we have: Sol:- y is simple interest on x, means y = (x*R*T)/100 RT = 100y/x z is simple interest on y, z = (y*R*T)/100 RT = 100z/y 100y/x = 100z/y y * y = xz 6.A Sum of Rs.1550 was lent partly at 5% and partly at 5% and partly at 8% p.a Simple interest .The total interest received after 3 years was Rs.300.The ratio of the money lent at 5% to that lent at 8% is: Sol:- Let the Sum at 5% be Rs x at 8% be Rs(1550-x) (x*5*3)/100 + ((1500-x)*8*3)/100 = 300 15x + 1500 * 24 - 24x = 30000 x = 800 Money at 5%/ Money at 8% = 800/(1550 - 800) = 800/750 = 16/15 7. A Man invests a certain sum of money at 6% p.a Simple interest and another sum at 7% p.a Simple interest. His income from interest after 2 years was Rs 354 .one fourth of the first sum is equal to one fifth of the second sum.The total sum invested was: Sol:- Let the sums be x & y R1 = 6 R2 = 7 T = 2 (P1*R1*T)/100 + (P2*R2*T)/100 = 354 (x * 6 * 2)/100 + (y * 7 * 2)/100 = 354 6x + 7y = 17700 鈥斺⌨️ 快捷键说明
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