📄 pipesandcisternscomplex.html~
字号:
<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" target="right"><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" target="right"><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" target="right"><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" target="right"><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" target="right"><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" target="right"><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" target="right"><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" target="right"><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" target="right"><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html" target="right"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" target="right"><strong>Areas</strong></a></TR><br><TR><a href="volume.html" target="right"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" target="right"><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" target="right"><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" target="right"><strong>Clocks</strong></a></TR><br><TR><a href="" target="right"><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" target="right"><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" target="right"><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html" target="right"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" target="right" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" target="right"><strong>Puzzles</strong></a></TR></table></TD><TD><a href="pipesandcisterns.html" target="right"><strong>BACK</strong></a><br><br><font size="5"><center><b><u>COMPLEX PROBLEMS</u></b></center></font><font size="4"><PRE>1)Two pipes can fill a cistern in 14 hours and 16 hours respectively. The pipesare opened simultaneously and it is found that due to leakage in the bottom it took 32min more to fill the cistern. When the cistern is full, in what time willthe leak empty it? Sol: Work done by the two pipes in 1 hour= 1/14+1/16=15/112 Time taken by these two pipes to fill the tank=112/15 hrs. Due to leakage, time taken = 7 hrs 28 min+ 32 min= 8 hours Therefore, work done by (two pipes + leak) in 1 hr= 1/8 work done by leak n 1 hour=15/112 -1/8=1/112 Leak will empty full cistern n 112 hours.2)Two pipes A&B can fill a tank in 30 min. First, A&B are opened. After 7 min,C also opened. In how much time, the tank s full.Sol: Part filled n 7 min = 7*(1/36+1/45)=7/20 Remaining part= 1-7/20=13/20 Net part filled in 1 min when A,B and C are opened=1/36 +1/45- 1/30=1/60 Now, 1/60 part is filled in 1 min. 13/20 part is filled n (60*13/20)=39 min Total time taken to fill the tank=39+7=46 min 3)Two pipes A&B can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min. Sol: Let B be closed after x min, then part filled by (A+B) in x min+ part filled by A in (18-x) min=1 x(1/24+1/32) +(18-x)1/24 =1 => x=8 Hence B must be closed after 8 min.4)Two pipes A& B together can fill a cistern in 4 hours. Had they been openedseparately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?Sol: Let the cistern be filled by pipe A alone in x hours. Pipe B will fill it in x+6 hours 1/x + 1/x+6=1/4 Solving this we get x=6. Hence, A takes 6 hours to fill the cistern separately.5)A tank is filled by 3 pipes with uniform flow. The first two pipes operatingsimultaneously fill the tan in the same time during which the tank is filled bythe third pipe alone. The 2nd pipe fills the tank 5 hours faster than first pipeand 4 hours slower than third pipe. The time required by first pipe is :Sol: Suppose, first pipe take x hours to fill the tank then B & C will take (x-5) and (x-9) hours respectively. Therefore, 1/x +1/(x-5) =1/(x-9) On solving, x=15 Hence, time required by first pipe is 15 hours.6)A large tanker can be filled by two pipes A& B in 60min and 40 min respectively. How many minutes will it take to fill the tanker from emptystate if B is used for half the time & A and B fill it together for the other half? Sol: Part filled by (A+B) n 1 min=(1/60 +1/40)=1/24 Suppose the tank is filled in x minutes Then, x/2(1/24+1/40)=1 => (x/2)*(1/15)=1 => x=30 min.7)Two pipes A and B can fill a tank in 6 hours and 4 hours respectively.If they are opened on alternate hours and if pipe A s opened first, in how many hours, the tank shall be full.Sol: (A+B)'s 2 hours work when opened alternatively =1/6+1/4 =5/12 (A+B)'s 4 hours work when opened alternatively=10/12=5/6 Remaining part=1 -5/6=1/6. Now, it is A's turn and 1/6 part is filled by A in 1 hour . So, total time taken to fill the tank=(4+1)= 5 hours.8)Three taps A,B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternatively,the tank will be full in.Sol: (A+B)'s 1 hour's work=1/12+1/15=9/60=3/20 (A+C)'s 1 hour's work=1/20+1/12=8/60=2/15 Part filled in 2 hours=3/20+2/15=17/60 Part filled in 2 hours=3/20+2/15= 17/60 Part filled in 6 hours=3*17/60 =17/20 Remaining part=1 -17/20=3/20 Now, it is the turn of A & B and 3/20 part is filled by A& B in 1 hour. Therefore, total time taken to fill the tank=6+1=7 hours9)A Booster pump can be used for filling as well as for emptying a tank. The capacity of the tank is 2400 m3. The emptying capacity of the tank is10 m3 per minute higher than its filling capacity and the pump needs 8 minuteslesser to empty the tank than it needs to fill it. What is the filling capacityof the pump?Sol: Let, the filling capacity of the pump be x m3/min Then, emptying capacity of the pump=(x+10) m3/min. So,2400/x 鈥⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -