quadmin.m
来自「Matlab numerical methods,examples of mat」· M 代码 · 共 117 行
M
117 行
function [p,yp,dp,dy,P] = quadmin(f,a,b,delta,epsilon)
%---------------------------------------------------------------------------
%QUADMIN Search for a minimum, using quadratic interpolation.
% Sample calls
% [p,yp,dp,dy,P] = quadmin('f',a,b,delta,epsilon)
% [p,yp,dp,dy] = quadmin('f',a,b,delta,epsilon)
% Inputs
% f name of the function
% a left endpoint of [a,b]
% b right endpoint of [a,b]
% delta convergence tolerance for the abscissas
% epsilon convergence tolerance for the ordinates
% Return
% p abscissa of the minimum
% yp ordinate of the minimum
% dp error bound for p
% dy error bound for yp
% P vector of iterations
%
% NUMERICAL METHODS: MATLAB Programs, (c) John H. Mathews 1995
% To accompany the text:
% NUMERICAL METHODS for Mathematics, Science and Engineering, 2nd Ed, 1992
% Prentice Hall, Englewood Cliffs, New Jersey, 07632, U.S.A.
% Prentice Hall, Inc.; USA, Canada, Mexico ISBN 0-13-624990-6
% Prentice Hall, International Editions: ISBN 0-13-625047-5
% This free software is compliments of the author.
% E-mail address: in%"mathews@fullerton.edu"
%
% Algorithm 8.3 (Local Minimum Search: Quadratic Interpolation).
% Section 8.1, Minimization of a Function, Page 416
%---------------------------------------------------------------------------
p0 = a;
maxj = 20;
maxk = 30;
big = 1e6;
err = 1;
k = 1;
P(k) = p0;
cond = 0;
h = 1;
if (abs(p0)>1e4), h = abs(p0)/1e4; end
while (k<maxk & err>epsilon & cond~=5)
f1 = (feval(f,p0+0.00001)-feval(f,p0-0.00001))/0.00002;
if (f1>0), h = -abs(h); end
p1 = p0 + h;
p2 = p0 + 2*h;
pmin = p0;
y0 = feval(f,p0);
y1 = feval(f,p1);
y2 = feval(f,p2);
ymin = y0;
cond = 0;
j = 0;
while (j<maxj & abs(h)>delta & cond==0)
if (y0<=y1),
p2 = p1;
y2 = y1;
h = h/2;
p1 = p0 + h;
y1 = feval(f,p1);
else
if (y2<y1),
p1 = p2;
y1 = y2;
h = 2*h;
p2 = p0 + 2*h;
y2 = feval(f,p2);
else
cond = -1;
end
end
j = j+1;
if (abs(h)>big | abs(p0)>big), cond=5; end
end
if (cond==5),
pmin = p1;
ymin = feval(f,p1);
else
d = 4*y1-2*y0-2*y2; %Start of a long block:
if (d<0),
hmin = h*(4*y1-3*y0-y2)/d;
else
hmin = h/3;
cond = 4;
end
pmin = p0 + hmin;
ymin = feval(f,pmin);
dh = abs(h);
h0 = abs(hmin);
h1 = abs(hmin-h);
h2 = abs(hmin-2*h);
if (h0<dh), h = h0; end
if (h1<dh), h = h1; end
if (h2<dh), h = h2; end
if (h==0), h = abs(hmin); end
if (h<delta), cond=1; end
if (abs(h)>big | abs(pmin)>big), cond=5; end
e0 = abs(y0-ymin);
e1 = abs(y1-ymin);
e2 = abs(y2-ymin);
if (e0~=0 & e0<err), err = e0; end
if (e1~=0 & e1<err), err = e1; end
if (e2~=0 & e2<err), err = e2; end
if (e0~=0 & e1==0 & e2==0), error=0; end
if (err<epsilon), cond=2; end
p0 = pmin;
k = k+1;
P(k) = p0;
end % End of the long block.
if (cond==2 & h<delta), cond=3; end
end
p = p0;
dp = h;
yp = feval(f,p);
dy = err;
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