operatorprecedence.pde

来自「This is processing for java examples.」· PDE 代码 · 共 59 行

PDE
59
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/** * Operator Precedence *  * If you don't explicitly state the order in which * an expression is evaluated, they are evaluated based * on the operator precedence. For example, in the statement * "4+2*8", the 2 will first be multiplied by 8 and then the result will * be added to 4. This is because the "*" has a higher precedence * than the "+". To avoid ambiguity in reading the program,  * it is recommended that is statement is written as "4+(2*8)". * The order of evaluation can be controlled through placement of * parenthesis in the code. A table of operator precedence follows below. *  */ // The highest precedence is at the top of the list and // the lowest is at the bottom.// Multiplicative: * / %// Additive: + -// Relational: < > <= >=// Equality: == !=// Logical AND: &&// Logical OR: ||// Assignment: = += -= *= /= %=size(200, 200);background(51);noFill();stroke(51);stroke(204);for(int i=0; i< width-20; i+= 4) {  // The 30 is added to 70 and then evaluated  // if it is greater than the current value of "i"  // For clarity, write as "if(i > (30 + 70)) {"  if(i > 30 + 70) {    line(i, 0, i, 50);  }}stroke(255);// The 2 is multiplied by the 8 and the result is added to the 5// For clarity, write as "rect(5 + (2 * 8), 0, 90, 20);"rect(4 + 2 * 8, 52, 90, 48);rect((4 + 2) * 8, 100, 90, 49);  stroke(153);for(int i=0; i< width; i+= 2) {  // The relational statements are evaluated   // first, and then the logical AND statements and   // finally the logical OR. For clarity, write as:  // "if(((i > 10) && (i < 50)) || ((i > 80) && (i < 160))) {"  if(i > 20 && i < 50 || i > 100 && i < width-20) {    line(i, 151, i, height-1);  } }

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