led.c

我做的显示程序

#include <AT89X52.h>
#include <intrins.h>
#include<math.h>
sbit DIN=P1^0;
sbit CLK=P1^1;
sbit LOAD=P1^2;
sbit KEY1=P1^3;
sbit KEY2=P1^4;
unsigned char KEYKEY=5;
void inputa(unsigned char  aa)
{unsigned char i=0,j=0;
unsigned char aab;
 float data_com[]={5.233,4.214,3.823,2.248,1.128};
for (i=1;i<=8;i++)
	{CLK=0;
	aab=aa;
	aab&=0x80;
	aab>>=7;
	DIN=aab;
	aa<<=1;
	CLK=1;
	for (j=0;j<2;j++)
	_nop_();
	CLK=0;
	}
}
void input(unsigned char  aa,unsigned char b)
{unsigned char i=0;
	LOAD=0;
	inputa(aa);
	inputa(b);
	LOAD=1;
for(i=0;i<2;i++);
}

void main()
{unsigned char i=0;
unsigned char c[]={1,1,3,5,1,5,4,6,0};
EA=1;
IE=0X84;
TCON=0X04;
CLK=0;
LOAD=0;
input(12,0);
input(9,255);
input(11,7);
input(10,15);
input(12,1);

//判断KEYKEY,即可知道按键情况
while(1)
{
switch (KEYKEY)
{case 5:
	for(i=1;i<9;i++)input(i,KEYKEY);break;
case 4:
case 6: for(i=1;i<9;i++)input(i,i);break;
case 3:
case 7: for (i=1;i<9;i++)input(i,i+1);break;
case 2:
case 8: for(i=1;i<9;i++)input(i,i+2);break;
case 1:
case 9: for(i=1;i<9;i++)input(i,i+3);break;
default: KEYKEY=5;
}
}
}

//利用全局变量KEYKEY，按键1使KEYKEY加1，按键2使KEYKEY减1.
int_1()interrupt 2
{if (KEY1==0)
	KEYKEY++;
if(KEY2==0)
	KEYKEY--;
}
bcdma(char *point)
{
unsigned char ge,shifen,baifen,qianfen,i=1;
//unsigned char gg[5][10];
float mm;
for(i=0;i<5;i++)
mm=point[i];
ge=(char)mm%10;
mm*=10;
shifen=(int)mm%10;
mm*=10;
baifen=(int)mm%10;
mm*=10;
qianfen=(int)mm%10;
}