📄 examp3_29.m
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x=[0:0.01:3*pi/2, 3*pi/2]; % 这样赋值能确保 $3\pi/2$ 点被包含在内
y=cos(15*x); plot(x,y)
syms x, A=int(cos(15*x),0,3*pi/2) % 求取理论值
h0=[0.1,0.01,0.001,0.0001,0.00001,0.000001]; v=[];
for h=h0,
x=[0:h:3*pi/2, 3*pi/2]; y=cos(15*x); I=trapz(x,y); v=[v; h,I,1/15-I];
end
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