copy.c

来自「math library from gnu」· C语言 代码 · 共 92 行

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/* gsl_histogram_copy.c * Copyright (C) 2000  Simone Piccardi * * This library is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License as * published by the Free Software Foundation; either version 3 of the * License, or (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU * General Public License for more details. * * You should have received a copy of the GNU General Public * License along with this library; if not, write to the * Free Software Foundation, Inc., 59 Temple Place - Suite 330, * Boston, MA 02111-1307, USA. *//*************************************************************** * * File gsl_histogram_copy.c:  * Routine to copy an histogram.  * Need GSL library and headers. * * Author: S. Piccardi * Jan. 2000 * ***************************************************************/#include <config.h>#include <stdlib.h>#include <gsl/gsl_errno.h>#include <gsl/gsl_histogram.h>/* * gsl_histogram_copy: * copy the contents of an histogram into another */intgsl_histogram_memcpy (gsl_histogram * dest, const gsl_histogram * src){  size_t n = src->n;  size_t i;  if (dest->n != src->n)    {      GSL_ERROR ("histograms have different sizes, cannot copy",                 GSL_EINVAL);    }  for (i = 0; i <= n; i++)    {      dest->range[i] = src->range[i];    }  for (i = 0; i < n; i++)    {      dest->bin[i] = src->bin[i];    }  return GSL_SUCCESS;}/* * gsl_histogram_duplicate: * duplicate an histogram creating * an identical new one */gsl_histogram *gsl_histogram_clone (const gsl_histogram * src){  size_t n = src->n;  size_t i;  gsl_histogram *h;  h = gsl_histogram_calloc_range (n, src->range);  if (h == 0)    {      GSL_ERROR_VAL ("failed to allocate space for histogram struct",                        GSL_ENOMEM, 0);    }  for (i = 0; i < n; i++)    {      h->bin[i] = src->bin[i];    }  return h;}

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