📄 dtimvec.m
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function npts=dtimvec(a,b,c,x0,st)
%DTIMVEC Returns a time vector for use with discrete time response
% functions.
%
% NPTS=DTIMVEC(a,b,c,X0,ST,PRECISION) returns a suggestion
% for the number of samples, NPTS. that should be used
% with discrete state space systems (a,b,c) that have known
% initial conditions X0. NPTS can be used,
% for instance, for step and impulse responses.
%
% DTIMVEC attempts to produce a number of points that ensures the
% output responses have decayed to approx. ST % of their initial
% or peak values.
% A.C.W.Grace 9-21-89
% Copyright (c) 1986-93 by the MathWorks, Inc.
[r,n]=size(c);
% Work out scale factors by looking at d.c. gain,
% eigenvectors and eigenvalues of the system.
[m,r]=eig(a);
r=diag(r);
% Equate the responses to the sum of a set of
% exponentials(r) multiplied by a vector of magnitude terms(vec).
[r1,n]=size(c);
if r1>1, c1=max(abs(c)); else c1=c; end
% Cater for the case when m is singular
if rcond(m)<eps
vec = (c1*m).'.*(1e4*ones(n,1));
else
vec=(c1*m).'.*(m\x0);
end
% Cater for the case when poles and zeros cancel each other out:
vec=vec+1e-20*(vec==0);
% d.c. gain (not including d matrix)
dcgain =c1*x0; % or dcgain=c\(eye(n)-a)*b;
ind=find(imag(r)>0);
% If the d.c gain is small then base the scaling
% factor on the estimated maximum peak in the response.
if abs(dcgain)<1e-8;
% Estimation of the maximum peak in the response.
peak=2*imag(vec(ind)).*exp(-abs(0.5*real(r(ind)).*pi./imag(r(ind))));
pk=max([abs(dcgain);abs(peak);eps]);
else
pk=dcgain;
end
% Work out the st% settling time for the responses.
% (or st% peak value settling time for low d.c. gain systems).
lt=(st*pk./abs(vec));
n1=log(lt)./log(abs(r)+(abs(r)==1));
n=max(real(n1));
% For unstable problems n will be negative
if n<=3, n=max(abs(n1))+2; end
n=min([n,1000]);
% Round the maximum time to an appropriate value for plotting.
nn=chop(n,1,5);
if abs((n-nn)/n)>0.2,
nn=chop(n,1,1);
if abs((n-nn)/n)>0.2
nn=chop(n,2,2);
end
end
npts=nn+1;
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