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📄 zebra.mod

📁 著名的大规模线性规划求解器源码GLPK.C语言版本,可以修剪.内有详细帮助文档.
💻 MOD
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/* ZEBRA, Who Owns the Zebra? *//* Written in GNU MathProg by Andrew Makhorin <mao@mai2.rcnet.ru> */#########################################################################  The Zebra Puzzle is a well-known logic puzzle.##  It is often called "Einstein's Puzzle" or "Einstein's Riddle"#  because it is said to have been invented by Albert Einstein as a boy,#  with the common claim that Einstein said "only 2 percent of the#  world's population can solve". It is also sometimes attributed to#  Lewis Carroll. However, there is no known evidence for Einstein's or#  Carroll's authorship.##  There are several versions of this puzzle. The version below is#  quoted from the first known publication in Life International#  magazine on December 17, 1962.##   1. There are five houses.#   2. The Englishman lives in the red house.#   3. The Spaniard owns the dog.#   4. Coffee is drunk in the green house.#   5. The Ukrainian drinks tea.#   6. The green house is immediately to the right of the ivory house.#   7. The Old Gold smoker owns snails.#   8. Kools are smoked in the yellow house.#   9. Milk is drunk in the middle house.#  10. The Norwegian lives in the first house.#  11. The man who smokes Chesterfields lives in the house next to the#      man with the fox.#  12. Kools are smoked in the house next to the house where the horse#      is kept.#  13. The Lucky Strike smoker drinks orange juice.#  14. The Japanese smokes Parliaments.#  15. The Norwegian lives next to the blue house.##  Now, who drinks water? Who owns the zebra?##  In the interest of clarity, it must be added that each of the five#  houses is painted a different color, and their inhabitants are of#  different national extractions, own different pets, drink different#  beverages and smoke different brands of American cigarettes. One#  other thing: In statement 6, right means your right.##  (From Wikipedia, the free encyclopedia.)########################################################################set HOUSE := { 1..5 };set COLOR := { "blue", "green", "ivory", "red", "yellow" };set NATIONALITY := { "Englishman", "Japanese", "Norwegian", "Spaniard",      "Ukranian" };set DRINK := { "coffee", "milk", "orange_juice", "tea", "water" };set SMOKE := { "Chesterfield", "Kools", "Lucky_Strike", "Old_Gold",      "Parliament" };set PET := { "dog", "fox", "horse", "snails", "zebra" };var color{HOUSE, COLOR}, binary;c1{h in HOUSE}: sum{c in COLOR} color[h,c] = 1;c2{c in COLOR}: sum{h in HOUSE} color[h,c] = 1;var nationality{HOUSE, NATIONALITY}, binary;n1{h in HOUSE}: sum{n in NATIONALITY} nationality[h,n] = 1;n2{n in NATIONALITY}: sum{h in HOUSE} nationality[h,n] = 1;var drink{HOUSE, DRINK}, binary;d1{h in HOUSE}: sum{d in DRINK} drink[h,d] = 1;d2{d in DRINK}: sum{h in HOUSE} drink[h,d] = 1;var smoke{HOUSE, SMOKE}, binary;s1{h in HOUSE}: sum{s in SMOKE} smoke[h,s] = 1;s2{s in SMOKE}: sum{h in HOUSE} smoke[h,s] = 1;var pet{HOUSE, PET}, binary;p1{h in HOUSE}: sum{p in PET} pet[h,p] = 1;p2{p in PET}: sum{h in HOUSE} pet[h,p] = 1;/* the Englishman lives in the red house */f2{h in HOUSE}: nationality[h,"Englishman"] = color[h,"red"];/* the Spaniard owns the dog */f3{h in HOUSE}: nationality[h,"Spaniard"] = pet[h,"dog"];/* coffee is drunk in the green house */f4{h in HOUSE}: drink[h,"coffee"] = color[h,"green"];/* the Ukrainian drinks tea */f5{h in HOUSE}: nationality[h,"Ukranian"] = drink[h,"tea"];/* the green house is immediately to the right of the ivory house */f6{h in HOUSE}:   color[h,"green"] = if h = 1 then 0 else color[h-1,"ivory"];/* the Old Gold smoker owns snails */f7{h in HOUSE}: smoke[h,"Old_Gold"] = pet[h,"snails"];/* Kools are smoked in the yellow house */f8{h in HOUSE}: smoke[h,"Kools"] = color[h,"yellow"];/* milk is drunk in the middle house */f9: drink[3,"milk"] = 1;/* the Norwegian lives in the first house */f10: nationality[1,"Norwegian"] = 1;/* the man who smokes Chesterfields lives in the house next to the man   with the fox */f11{h in HOUSE}:   (1 - smoke[h,"Chesterfield"]) +   (if h = 1 then 0 else pet[h-1,"fox"]) +   (if h = 5 then 0 else pet[h+1,"fox"]) >= 1;/* Kools are smoked in the house next to the house where the horse is   kept */f12{h in HOUSE}:   (1 - smoke[h,"Kools"]) +   (if h = 1 then 0 else pet[h-1,"horse"]) +   (if h = 5 then 0 else pet[h+1,"horse"]) >= 1;/* the Lucky Strike smoker drinks orange juice */f13{h in HOUSE}: smoke[h,"Lucky_Strike"] = drink[h,"orange_juice"];/* the Japanese smokes Parliaments */f14{h in HOUSE}: nationality[h,"Japanese"] = smoke[h,"Parliament"];/* the Norwegian lives next to the blue house */f15{h in HOUSE}:   (1 - nationality[h,"Norwegian"]) +   (if h = 1 then 0 else color[h-1,"blue"]) +   (if h = 5 then 0 else color[h+1,"blue"]) >= 1;solve;printf "\n";printf "HOUSE  COLOR   NATIONALITY  DRINK         SMOKE         PET\n";for {h in HOUSE}{  printf "%5d", h;   printf{c in COLOR: color[h,c]} "  %-6s", c;   printf{n in NATIONALITY: nationality[h,n]} "  %-11s", n;   printf{d in DRINK: drink[h,d]} "  %-12s", d;   printf{s in SMOKE: smoke[h,s]} "  %-12s", s;   printf{p in PET: pet[h,p]} "  %-6s", p;   printf "\n";}printf "\n";end;

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