code1.cpp

实现在10……-6内固定求和表达式的上限

#include<iostream.h>
#include<math.h>
#include<stdlib.h>
#include<stdio.h>
void main()
{   
	long int k;
	double fai;
	
	double x[42];
double f[42]={0,1.6449,1.53460,1.440878,1.312323,1.2895,1.22741127,1.1721051,1.122519,1.077752,1.037110,1.0,0.2928,0.17988,0.1331662,0.1069636,0.08998411,0.07799784,0.06904053,0.06206849,0.05647301,0.05187378,0.04802031,0.04474057,0.04191224,0.03944589,0.03727454,0.03534695,0.03362325,0.03207193,0.03066773,0.02939015,0.02822239,0.02715052,0.02616290,0.02524974,0.02440270,0.02361469,0.022,0.02219211,0.021545,0.02094};
    x[0]=0.0;
	x[1]=0.0;
	for(int j=2;j<=11;j++)
	{
		x[j]=0.1*(j-1);

	}
	for(int h=12;h<=41;h++)
	{
		x[h]=(h-11)*10;
	}
	for(j=0;j<=41;j++)
	{
		cout<<x[j]<<" "<<f[j]<<endl;
	
	}
	cout<<"K :"<<"    "<<"fai:   "<<"x:   "<<endl;

for(int i=1;i<=41;i++)
{
     fai=0.0;
	 for(k=1;k<10000000;k++)
		 
{
	 fai=fai+(1.0/k)*(1.0/(k+x[i]));
	     
		 	 
		 if(f[i]-fai<0.000001)
		{
			// cout<<"K :"<<"    "<<"fai:   "<<"x:   "<<endl;

		cout<<"k : "<<k<<" "<<"fai: "<<fai<<" "<<"x:"<<x[i]<<endl;
          
		break;

}
	 }

}
}