login_ajax.php

无刷新技术AJAX,就是在不刷新网页的情况下更新网站内容

<?php
header( "Content-type: text/html; charset=gbk");
header( "Expires: Mon, 26 Jul 1997 05:00:00 GMT" );
header( "Last-Modified: " . gmdate( "D, d M Y H:i:s" ) . " GMT" );
header( "Cache-Control: no-cache, must-revalidate" );
header( "Pragma: no-cache" );

?>
<?php
require("public.php");
?>
<?php
//本例子是给ajax方式登录而准备的，而登录设置没有必要ajax化，采用传统就可以，
//这里只是为了演示方便而已
if( $loginSuccessful ){
  echo "<div style=\"position:absolute;top:10px;left:0;text-align:right;width:98%\">欢迎您：<b>". $adminName ."</b> <a href=\"javascript:logoutSub('login/logout.php')\">注销</a></div>";
}else{
?>
<hr size="0" style="border-top:1px solid gray">
<form action="login/loginValidate.php" method="post" onsubmit="return loginSub(this);" style="padding:10px;line-height:24px;">
姓名：<input name="name" value="<?php echo $adminName;?>" type="text" size="20">test<br>
密码：<input name="password" value="<?php echo $adminPassWord;?>" type="text" size="20">test<br>
验证：<input type="text" name="code" value="" maxlength="4" size="4">&nbsp;<img src="validate/img.php" valign="bottom" hspace="5" id="codeimg"><a href="javascript:reshow('codeimg');">看不清</a><br>
<input type="submit" value=" 提交 " size="" style="margin-left:45px"><br>
<div id="subinfo" style="color:red"></div>
</form>
<?php
 exit;
}

?>