📄 ajaxservlet.java
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package cn.liu.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class AJAXServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request, response);
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
//System.out.println("in");
String no = request.getParameter("no");
System.out.println(no);
//1.这里的message的数据应该是根据no从数据库中查出来的,然后让liulinbo-it-work
//这种格式组织起来
//2.message="liulinbo-it-work"是根据no在数据库中查到了相应的记录
//String message = "liulinbo-it-work";
//3.message=""是根据no没有查出对应的记录
String message = "";
if("001".equals(no)){
message = "liulinbo-it-work";
}
response.getWriter().print(message);
}
}
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