mipt001.cpp

来自「El Judge MIPT solutions to some easy pro」· C++ 代码 · 共 16 行

/*
Alfonso Alfonso Peterssen
2 - 2 - 2008
MIPT #001 "Max of Integers"
*/
#include <iostream>

using namespace std;

int main() {
    int max_n, x;
    for ( cin >> max_n; cin >> x; max_n >?= x );
    cout << max_n << endl;
    return 0;
}