acstest.java

简单算法结构,控制台输出,算法结构,可以下来看看,对初学者有启发

package com.accp.test;

import java.util.Scanner;

import com.accp.sys.ControlSys;
import com.accp.user.Admin;
import com.accp.user.Employee;
import com.accp.user.Guest;

public class AcsTest {
	ControlSys cs = new ControlSys();
	
	public void showMenu() {
		Scanner sc = new Scanner(System.in);
		String ans = "y";
		
		while(ans.equalsIgnoreCase("y")) {
			System.out.println("======门禁系统测试======");
			System.out.println("=     1、访客测试      =");
			System.out.println("=     2、顾员测试      =");
			System.out.println("=     3、管理员测试    =");
			System.out.println("=======================");
			System.out.print("请选择菜单项:");
			String choose = sc.next();
			if(choose.equals("1")) {
				testGuest();
			} else if(choose.equals("2")) {
				testEmployee();
			} else if(choose.equals("3")) {
				testAdmin();
			} else {
				System.out.println("选择错误!");
				continue;
			}
			System.out.print("是否继续测试(y/n)?");
			sc = new Scanner(System.in);
			ans = sc.next();
		}
	}
	
	public void testGuest() {
		Guest guest = new Guest("小白");
		guest.pressRing(cs);
		Admin admin = new Admin("小黑");
		admin.work(cs);
		cs.work();
	}
	
	public void testEmployee() {
		Employee emp = new Employee("晓晓");
		emp.input(cs);
		cs.work();
	}
	
	public void testAdmin() {
		
	}
	
	public static void main(String[] args) {
		new AcsTest().showMenu();
	}
}