numberit
来自「UNIX+shell范例精解(第4版)代码」· 代码 · 共 17 行
TXT
17 行
#!/bin/ksh# Program name: numberit# Put line numbers on all lines of memoif (( $# < 1 ))then print "Usage: $0 filename " >&2 exit 1fiinteger count=1 # Initialize countcat $1 | while read line # Input is coming from memodo (( count == 1 )) && print "Processing file $1..." > /dev/tty print $count $line (( count+=1 ))done > tmp$$ # Output is going to a temporary filemv tmp$$ $1
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