numberit

来自「UNIX+shell范例精解(第4版)代码」· 代码 · 共 17 行

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#!/bin/ksh# Program name: numberit# Put line numbers on all lines of memoif (( $# < 1 ))then	print "Usage: $0 filename " >&2	exit 1fiinteger count=1              # Initialize countcat $1 | while read line     # Input is coming from memodo 	(( count == 1 )) && print "Processing file $1..." > /dev/tty   	print $count $line 	(( count+=1 ))done > tmp$$                 # Output is going to a temporary filemv tmp$$ $1

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