📄 testa_pbar2.out
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Jun 18 2002
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*********************************************************************
* FEMjr v 2.0 - Finite Element Method junior - An FEM framework *
*********************************************************************
Enter name of input data file:
inputfile =
testa_pbar2.dat
<<<<---- Data File Echo ---->>>>
TITLE - Four bars in series; applied loads and displ's. Same as testa but using equivalent bars.
NODES - # of nodes: 5; # of dimensions: 1
# ID x y z
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
ELEMENTS - # of elements: 4
# ID elemType propID connectivity
5 1 pBar2 1 1 2
5 2 pBar2 2 2 3
5 3 pBar2 3 3 4
5 4 pBar2 4 4 5
PROPERTIES - # of properties: 4
# ID propType properties
1 1 MatpBar 25 1 0 0
2 2 MatpBar 20 1 0 0
3 3 MatpBar 40 1 0 0
4 4 MatpBar 10 1 0 0
CONSTRAINTS - # of constraints: 2
# nodeID dof value
1 2 1 0.2
2 5 1 0
LOADS - # of loads: 3
# nodeID dof value
1 1 1 2
2 3 1 -3
3 4 1 -1
ke =
25 -25
-25 25
fe =
0
0
ke =
20 -20
-20 20
fe =
0
0
ke =
40 -40
-40 40
fe =
0
0
ke =
10 -10
-10 10
fe =
0
0
Stiffness Matrix and Load Vector after assembly
kglobal =
25 -25 0 0 0
-25 45 -20 0 0
0 -20 60 -40 0
0 0 -40 50 -10
0 0 0 -10 10
load_vector =
0
0
0
0
0
Load Vector after assembly of point loads
load_vector =
2
0
-3
-1
0
Constrained Stiffness Matrix and Load Vector
STIFFNESS MATRIX
r/c 1 2 3 4 5 6 7 8
1 25 0 0 0 0
2 0 45 0 0 0
3 0 0 60 -40 0
4 0 0 -40 50 0
5 0 0 0 0 10
LOAD VECTOR
Row Value
1 7
2 9
3 1
4 -1
5 0
<<<<---- Solution Results ---->>>>
SOLUTION VECTOR
dof# value
1 0.28
2 0.2
3 0.0071429
4 -0.014286
5 0
Strain Energy (assume homogeneous displacement BCs) = 1.890714
ELEMENTAL POSTPROCESSING
ID f_i Sxx(end nodes) energy
1 2 -2 -2 -2 0.08
stress_nd =
-2.0000 -2.0000
ID f_i Sxx(end nodes) energy
2 3.86 -3.86 -3.86 -3.86 0.372
stress_nd =
-3.8571 -3.8571
ID f_i Sxx(end nodes) energy
3 0.857 -0.857 -0.857 -0.857 0.00918
stress_nd =
-0.8571 -0.8571
ID f_i Sxx(end nodes) energy
4 -0.143 0.143 0.143 0.143 0.00102
stress_nd =
0.1429 0.1429
Strain Energy = 0.462143
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