1.100 3.asm

汇编语言“自然数1到100的求和。并写出结果输出”

DATAS SEGMENT 
BuF DB 1,2,3,4,^^^^^^^,100 
BuF2 DW ? 
DATAS ENDS 

CODES SEGMENT 
ASSUME CS:CODES,DS:DATAS 
START: 
MOV AX,DATAS 
MOV DS,AX 
MOV SI,OFFSET BuF 
MOV CL,100 
MOV AX,0 
KK: ADC AX,[SI] 
INC SI 
LOOP KK 
MOV BuF2,AX 
MOV AH,4CH 
INT 21H 
CODES ENDS 
END START