stbc.m

来自「一些关于空时编码的编码解码仿真程序」· M 代码 · 共 12 行

function [out] = STBC(input)

[K,D,N,G,N_t,N_r,L,C]= header;
%input: 1 by D*N

temp = reshape(input,N_t,D,N/N_t);

out = zeros(N_t,D,N);
for n = 1:N/N_t,
        out(:,:,2*n-1) = temp(:,:,n);
        out(:,:,2*n) = [-conj(temp(2,:,n));conj(temp(1,:,n))];
end