logincontroller.java

java中如何对Spring技术使用的示范代码！代码详细。

package user;

import java.util.List;

import org.springframework.web.servlet.mvc.*;
import org.springframework.web.servlet.*;
import org.springframework.web.bind.*;
import org.springframework.beans.factory.BeanFactory;
import org.springframework.beans.factory.xml.XmlBeanFactory;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.validation.*;
import java.util.*;

public class LoginController extends SimpleFormController{
	
	private String login_success;
	private String login_fail;
	
	public ModelAndView onSubmit(Object command,BindException ex) throws Exception{
		
		User user=(User)command;
		
		Resource resource=new ClassPathResource("applicationContext.xml");
		BeanFactory factory=new XmlBeanFactory(resource);	
		UserDAO dao=(UserDAO)factory.getBean("UserDAO");

		List userlist=dao.findByExample(user);
		
		HashMap model = new HashMap();
		
		if(!userlist.isEmpty())
		{
			model.put("userName", user.getUserName());
			
			return new ModelAndView(this.getLogin_success() , model);
		}
		else
		{
			model.put("userName", user.getUserName());
			
			return new ModelAndView(this.getLogin_fail() , model);
		}
	}
	
	public String getLogin_fail() {
		return login_fail;
	}
	public void setLogin_fail(String login_fail) {
		this.login_fail = login_fail;
	}
	public String getLogin_success() {
		return login_success;
	}
	public void setLogin_success(String login_success) {
		this.login_success = login_success;
	}
}