points.js

来自「对java中如何使用Ajax技术」· JavaScript 代码 · 共 55 行

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/*	Copyright (c) 2004-2006, The Dojo Foundation	All Rights Reserved.	Licensed under the Academic Free License version 2.1 or above OR the	modified BSD license. For more information on Dojo licensing, see:		http://dojotoolkit.org/community/licensing.shtml*/dojo.provide("dojo.math.points");dojo.require("dojo.math");dojo.math.points = {	translate: function(/* array */a, /* array */b) {		//	summary		//	translate a by b, and return the result.		if( a.length != b.length ) {			dojo.raise("dojo.math.translate: points not same size (a:[" + a + "], b:[" + b + "])");		}		var c = new Array(a.length);		for(var i = 0; i < a.length; i++) {			c[i] = a[i] + b[i];		}		return c;	//	array	},	midpoint: function(/* array */a, /* array */b) {		//	summary		//	Find the point midway between a and b		if( a.length != b.length ) {			dojo.raise("dojo.math.midpoint: points not same size (a:[" + a + "], b:[" + b + "])");		}		var c = new Array(a.length);		for(var i = 0; i < a.length; i++) {			c[i] = (a[i] + b[i]) / 2;		}		return c;	//	array	},	invert: function(/* array */a) {		//	summary		//	invert the values in a and return it.		var b = new Array(a.length);		for(var i = 0; i < a.length; i++) { b[i] = -a[i]; }		return b;	//	array	},	distance: function(/* array */a, /* array */b) {		//	summary		//	Calculate the distance between point a and point b		return Math.sqrt(Math.pow(b[0]-a[0], 2) + Math.pow(b[1]-a[1], 2));	// 	float	}};

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