fmpower.m

一个很有用的MATLAB7.0时频分析工具箱

function [x,iflaw]=fmpower(N,k,p1,p2)
%FMPOWER Signal with power-law frequency modulation.
%	[X,IFLAW]=FMPOWER(N,K,P1,P2) generates a signal with a
%	power-law frequency modulation.
%	X(t) = exp(j*2*pi(F0*t + C/(1-K)*abs(t).^(1-K))) 
%
%	N  : number of points in time
%	K  : degree of the power-law (K~=1)
%	P1 : if the number of input arguments (NARGIN) is 3, P1 is a 
%	    vector containing the two coefficients [F0 C] for a
%	    power-law instantaneous frequency (sampling frequency is set to 1).
%	    If NARGIN=4, P1 (as P2) is a time-frequency point of the 
%	    form [Ti Fi]. Ti is in seconds and Fi is a normalized frequency
%	    (between 0 and 0.5). The coefficients F0 
%	    and C are then deduced such that the frequency modulation 
%	    law fits the points P1 and P2.
%	P2 : same as P1 if NARGIN=4         (optional)
%	X  : time row vector containing the modulated signal samples
%	IFLAW : instantaneous frequency law
%
%	Examples :   
%	 [X,IFLAW]=fmpower(128,0.5,[1 0.5],[100 0.1]);
%	 subplot(211);plot(real(X));subplot(212);plot(IFLAW);
%
%	See also GDPOWER, FMCONST, FMLIN, FMHYP, FMPAR, FMODANY, FMSIN.

%	P. Goncalves - October 1995, O. Lemoine - April 1996.
%	Copyright (c) 1995 Rice University, 1996 CNRS (France).
%
%	------------------- CONFIDENTIAL PROGRAM -------------------- 
%	This program can not be used without the authorization of its
%	author(s). For any comment or bug report, please send e-mail to 
%	[e-mail] 

if (nargin <= 2),
 error ( 'The number of parameters must be at least 3.' );
elseif (N <= 0),
 error ('The signal length N must be strictly positive' );
elseif abs(k-1)<sqrt(eps),
  error('K must be different from 1');
elseif nargin == 3
  if length(p1) ~= 2
   error('Bad number of coefficients');
  end
  f0 = p1(1) ; c = p1(2) ;
elseif nargin == 4 ;
  if (length(p1) ~= 2) |(length(p2) ~= 2),
   error('Bad number of coefficients for P1 or P2');
  end
  if p1(1)>N | p1(1)<1,
   error ('P1(1) must be between 1 and N');
  elseif p2(1)>N | p2(1)<1,
   error ('P2(1) must be between 1 and N');
  elseif p1(2)<0,
   error ('P1(2) must be > 0');
  elseif p2(2)<0,
   error ('P2(2) must be > 0');
  end
  c  = (p2(2) - p1(2))/(1/p2(1)^k - 1/p1(1)^k) ;
  f0 = p1(2) - c/p1(1)^k ;
end  

t=1:N;

phi = 2*pi*(f0*t + c/(1-k)*abs(t).^(1-k)) ;
iflaw = (f0 + c*abs(t).^(-k)).' ;

aliasing = find(iflaw<0 | iflaw>0.5) ;
if isempty(aliasing) == 0
  disp(['!!! WARNING: signal is undersampled or has negative frequencies']) ;
end

x = exp(i*phi).';