📄 func_default.result
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drop table if exists t1,t2;create table t1(str varchar(10) default 'def',strnull varchar(10),intg int default '10',rel double default '3.14');insert into t1 values ('','',0,0.0);select default(str), default(strnull), default(intg), default(rel) from t1;default(str) default(strnull) default(intg) default(rel)def NULL 10 3.14explain extended select default(str), default(strnull), default(intg), default(rel) from t1;id select_type table type possible_keys key key_len ref rows Extra1 SIMPLE t1 system NULL NULL NULL NULL 1 Warnings:Note 1003 select default(`test`.`t1`.`str`) AS `default(str)`,default(`test`.`t1`.`strnull`) AS `default(strnull)`,default(`test`.`t1`.`intg`) AS `default(intg)`,default(`test`.`t1`.`rel`) AS `default(rel)` from `test`.`t1`select * from t1 where str <> default(str);str strnull intg rel 0 0explain select * from t1 where str <> default(str);id select_type table type possible_keys key key_len ref rows Extra1 SIMPLE t1 system NULL NULL NULL NULL 1 drop table t1;CREATE TABLE t1 (id int(11), s varchar(20));INSERT INTO t1 VALUES (1, 'one'), (2, 'two'), (3, 'three');SELECT s, 32 AS mi FROM t1 GROUP BY s HAVING DEFAULT(mi) IS NULL;ERROR HY000: Field 'mi' doesn't have a default valueDROP TABLE t1;
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