📄 sa_ex7_14.m
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% root-Min-Norm AOA estimation for a M = 4 element array with noise variance = .1
% use time averages instead of expected values by assuming ergodicity of the mean and
% ergodicity of the correlation.
% First solve the regular MUSIC problem, calculate polynomial coefficients for root-MUSIC,
% and plot comparing the two methods.
%
randn('state',0)
M=4;
D = 2; % number of signals
sig1=1;
sig2=.3;
th1=-2*pi/180;
th2=4*pi/180;
temp=eye(M);
u1=temp(:,1);
a1=[1];
a2=[1];
for i=2:M
a1=[a1 exp(-1j*i*pi*sin(th1))];
a2=[a2 exp(-1j*i*pi*sin(th2))];
end
A=[a1.' a2.'];
K=300; % K = length of time samples
s=sqrt(sig1)*sign(randn(D,K)); % calculate the K time samples of the signals for the
% two arriving directions
Rss=s*s'/K; % source correlation matrix with uncorrelated signals
n=sqrt(sig2)*randn(M,K); % calculate the K time samples of the noise for the 6 array
% elements
Rnn=(n*n')/K; % calculate the noise correlation matrix (which is no longer diagonal)
Rns=(n*s')/K; % calculate the noise/signal correlation matrix
Rsn=(s*n')/K; % calculate the signal/noise correlation matrix
Rrr=A*Rss*A'+A*Rsn+Rns*A'+Rnn; % combine all to get the array correlation matrix
[V,Dia]=eig(Rrr);
[Y,Index]=sort(diag(Dia)); % sorts the eigenvalues from least to greatest
EN=V(:,Index(1:M-D)); % calculate the noise subspace matrix of eigenvectors
% using the sorting done in the previous line
for k=1:360;
th(k)=-pi/12+pi*k/(6*360);
clear a
a=[1];
for jj=2:M
a = [a exp(-1j*jj*pi*sin(th(k)))];
end
a=a.';
P(k)=1/abs(a'*EN*EN'*u1)^2;
end
c1=(EN*EN')*u1;
C=c1*c1'; % calculate the matrix C
% Find the coefficients for the root-MUSIC polynomial
for kk=-M+1:M-1
cc(kk+M) = sum(diag(C,kk));
end
rts=roots(cc); % find the roots of the 2*(M-1) polynomial
angs=asin(angle(rts)/pi)*180/pi % find the angles associated with these root
figure;zplane(rts)
figure;
plot(th*180/pi,P/max(P),'k',angs,abs(rts),'kX','markersize',10)
grid on
xlabel('Angle')
ylabel('|P(\theta)|')
axis([-10 10 0 1.6])
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