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📄 hangkongdingpiao.c

📁 数据结构课程设计用C实现的航空订票系统
💻 C
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}	

int ReturnOpOrd(char op,char* TestOp) {//被char precede(char Aop, char Bop)所调用来求优先级
   int i;
   for(i=0; i< OPSETSIZE; i++) {
      if (op == TestOp[i]) return i;
   }
   return 0;
}

char precede(char Aop, char Bop) {
	return Prior[ReturnOpOrd(Aop,OPSET)][ReturnOpOrd(Bop,OPSET)];   
}

status initstack(sqstack *s){
	(s)->base = (int*)malloc(STACK_INIF_SIZE*sizeof(int));
	if((s)->base==NULL) exit(OVERFLOW);
	(s)->top=(s)->base;
	(s)->stacksize = STACK_INIF_SIZE;
//	printf("栈初始化完成!\n");
	return OK;	
	}

int gettop(sqstack *s){
		int e;
		if(s->top==s->base){
			 printf("栈空,无法取得栈顶元素!\n");
			 return 0;
			 }
		e=*(s->top-1);
//		printf("取得栈顶元素: %d \n",e);
		return e;
		}

status push(sqstack *s,int e){
	if(s->top-s->base>=s->stacksize){
		s->base=(int*)realloc(s->base,(s->stacksize+STACKINCREMENT)*sizeof(int));
		if(!s->base) exit(OVERFLOW);
		s->stacksize+= STACKINCREMENT;
		}
	*(s->top++)=e;
//    printf("把 %d 压栈 is OK\n",e);
	return OK;
	}

status pop(sqstack *s,int *e){
	if(s->top==s->base){
		printf("栈空,出栈错误!\n");
		return ERROR;
		}
	*e=*(--s->top);
//    printf("	%d出栈成功 !\n",*e);
	return OK;
	}

int EvaluateExpression(char* MyExpression) {  // 算法3.4
   // 算术表达式求值的算符优先算法。
   // 设OPTR和&&OPND分别为运算符栈和运算数栈,OP为运算符集合。
	int result;
	sqstack  OPTR;    // 运算符栈,字符元素
   sqstack  OPND;    // 运算数栈,实数元素
   int c,bl,a,b,theta,top;
   sqlist *q,l;  
   char *s=MyExpression;
   init_sq(&l);
   if(chang(s,&l)!=0){
   q=&l;
   initstack(&OPTR);
   push(&OPTR, 35);
   initstack (&OPND);
   q=q->next;
   c=q->num_ch;
   bl=q->bol;
   while ((c!= 35 || gettop(&OPTR)!=35)){
//	   printf("while start!\n");
      if (bl!=1) {
         push(&OPND, c);
		 q=q->next;
		 c=q->num_ch;
		 bl=q->bol;
         } // 不是运算符则进栈
     else {  
		 top=gettop(&OPTR);
//		 printf("top  %c",top);
		 switch (precede(top, c)) { 
            case '<': 
			  // 栈顶元素优先权低
                 push(&OPTR, c);  				 
					 q=q->next;
					 c=q->num_ch;								 
					 bl=q->bol; 
                 break;
            case '=':   // 脱括号并接收下一字符
                 pop(&OPTR, &c);   				 
					 q=q->next;
					 c=q->num_ch;								 
					 bl=q->bol; 
                 break;
            case '>':   // 退栈并将运算结果入栈
                 pop(&OPTR, &theta);
                 pop(&OPND, &b);  
                 pop(&OPND, &a);
	//			 printf("q->num_ch is %d\n",q->num_ch);
                 push(&OPND, Operate(a, theta, b)); 		
                 break;
			default :
				printf("没有这个运算符!\n");
				return 0;
         } // switch
      }//else
   } // while
   result=gettop(&OPND);
   return result;
   }
   else {
	   printf("你的输入有错误!\n");
	   return 0;
   }
} // EvaluateExpression

int randomm()//产生四个随机数
{	
	
	int i=0;
	srand((unsigned)time(NULL));
	for (;i<4;i++){
		number[0][i]=0;
		number[0][i]=rand();
		number[0][i]%=13;
		number[0][i]++;
		number[1][i]=0;
	}
	return number[2][4];
}


 int CalcOneExpress(int expression[][2])
 {
	    // 算术表达式求值的算符优先算法。
   // 设OPTR和&&OPND分别为运算符栈和运算数栈,OP为运算符集合。
	int index=0,result,c,theta,a,b;
	sqstack  OPTR;    // 运算符栈,字符元素
   sqstack  OPND;    // 运算数栈,实数元素
   initstack(&OPTR);
   push(&OPTR, 35);
   initstack (&OPND);
   c=expression[index][0];
   while (c!= 35 || gettop(&OPTR)!=35){
      if (expression[index][1]!=1) {
         push(&OPND, c);
		 index++;
		 c=expression[index][0];
		 
         } // 不是运算符则进栈
     else {  		 
		 switch (precede(gettop(&OPTR), c)) { 
            case '<': 
			  // 栈顶元素优先权低
                 push(&OPTR, c);  				 
					 index++;
					 c=expression[index][0];								 					  
                 break;
            case '=':   // 脱括号并接收下一字符
                 pop(&OPTR, &c);   				 
					 index++;
					 c=expression[index][0];								 					  
                 break;
            case '>':   // 退栈并将运算结果入栈
                 pop(&OPTR, &theta);
                 pop(&OPND, &b);  
                 pop(&OPND, &a);
                 push(&OPND, Operate(a, theta, b)); 		
                 break;
			default :
				printf("没有这个运算符\n");
				return 0;
         } // switch
      }//else
   } // while
   result=gettop(&OPND);
//   printf("the result is %d\n",result);
   return result;
} // EvaluateExpression

 int Equal24(int n)
 {
	 if(n==24){
//		 printf("the result is %d\n",n);
		 return TRUE;
	 }
	 else    return FALSE;
 }

 	//括号的几种情况
	//1	无括号
	//2 (a b) c d		同a b (c d), 下省略
	//3 (a b c) d
	//4 a (b c) d
	//5 (a b) (c d)
	//6 ((a b) c) d
	//7 (a (b c)) d
int CalcArray1(int iNumInput[2][4])
{
	// a * b * c * d	//7 number
	int expression[8][2],ii,jj,kk;
	int i,j,k,l,dRes;
	
    for(i=0;i<4;i++)
    {
        for(j=0;j<4;j++)    
        {
            if(j==i)
            {
                continue;
            }
            for(k=0;k<4;k++)
            {
                if(k==i||k==j)
                {
                    continue;
                }
                for(l=0;l<4;l++)
                {
                    if(l==i||l==j||l==k)
                    {
                        continue;
                    }
                    expression[0][0]=iNumInput[0][i];
                    expression[2][0]=iNumInput[0][j];
                    expression[4][0]=iNumInput[0][k];
                    expression[6][0]=iNumInput[0][l];

					expression[0][1]=eNumber;
					expression[2][1]=eNumber;
					expression[4][1]=eNumber;
					expression[6][1]=eNumber;
					for (ii=0;ii<4;ii++)
					{
						for (jj=0;jj<4;jj++)
						{
							for (kk=0;kk<4;kk++)
							{

									expression[1][0] = oper[ii];
									expression[1][1] = eOperator;
									expression[3][0] = oper[jj];
									expression[3][1] = eOperator;
									expression[5][0] = oper[kk];
									expression[5][1] = eOperator;
									expression[7][0] = oper[6];
									expression[7][1] = eOperator;																	
									dRes = CalcOneExpress(expression);
									if(Equal24(dRes))
									{
										printf("可以这样运算:%d%c%d%c%d%c%d\n",expression[0][0],oper[ii],expression[2][0],oper[jj],expression[4][0],oper[kk],expression[6][0]);
										return TRUE;										
									}								
							}
						}
					}//end of for oper
				}
			}
		}
	}
	
	return FALSE;
}

int CalcArray2(int iNumInput[2][4])
{
	// (a * b) * c * d	//9 number
	int expression[10][2];
	int ii,jj,i,j,k,l,kk;
	int dRes;
//	printf("CalcArray2\n");
    for(i=0;i<4;i++)
    {
        for(j=0;j<4;j++)    
        {
            if(j==i)
            {
                continue;
            }
            for(k=0;k<4;k++)
            {
                if(k==i||k==j)
                {
                    continue;
                }
                for(l=0;l<4;l++)
                {
                    if(l==i||l==j||l==k)
                    {
                        continue;
                    }
                    expression[1][0]=iNumInput[0][i];
                    expression[3][0]=iNumInput[0][j];
                    expression[6][0]=iNumInput[0][k];
                    expression[8][0]=iNumInput[0][l];

					expression[1][1]=eNumber;
					expression[3][1]=eNumber;
					expression[6][1]=eNumber;
					expression[8][1]=eNumber;
					for (ii=0;ii<4;ii++)
					{
						for (jj=0;jj<4;jj++)
						{
							for (kk=0;kk<4;kk++)
							{

									expression[2][0] = oper[ii];
									expression[2][1] = eOperator;
									expression[5][0] = oper[jj];
									expression[5][1] = eOperator;
									expression[7][0] = oper[kk];
									expression[7][1] = eOperator;
									expression[9][0] = oper[6];
									expression[9][1] = eOperator;
									expression[0][0] = oper[4];
									expression[0][1] = eOperator;
									expression[4][0] = oper[5];
									expression[4][1] = eOperator;
									
									dRes = CalcOneExpress(expression);
									if(Equal24(dRes))
									{
										printf("可以这样运算:%c%d%c%d%c%c%d%c%d\n",oper[4],expression[1][0],oper[ii],expression[3][0],oper[5],oper[jj],expression[6][0],oper[kk],expression[8][0]);
										return TRUE;										
									}								
							}
						}
					}//end of for oper
				}
			}
		}
	}

	return FALSE;
}


int CalcArray3(int iNumInput[2][4])
{
	// (a * b * c) * d	//9 number
	int expression[10][2];
	int ii,jj,i,j,k,l,kk;
	int dRes;
//	printf("CalcArray3\n");
    for(i=0;i<4;i++)
    {
        for(j=0;j<4;j++)    
        {
            if(j==i)
            {
                continue;
            }
            for(k=0;k<4;k++)
            {
                if(k==i||k==j)
                {
                    continue;
                }
                for(l=0;l<4;l++)
                {
                    if(l==i||l==j||l==k)
                    {
                        continue;
                    }
                    expression[1][0]=iNumInput[0][i];
                    expression[3][0]=iNumInput[0][j];
                    expression[5][0]=iNumInput[0][k];
                    expression[8][0]=iNumInput[0][l];

					expression[1][1]=eNumber;
					expression[3][1]=eNumber;
					expression[5][1]=eNumber;
					expression[8][1]=eNumber;
					for (ii=0;ii<4;ii++)
					{
						for (jj=0;jj<4;jj++)
						{
							for (kk=0;kk<4;kk++)
							{

									expression[2][0] = oper[ii];
									expression[2][1] = eOperator;
									expression[4][0] = oper[jj];
									expression[4][1] = eOperator;
									expression[7][0] = oper[kk];
									expression[7][1] = eOperator;
									expression[9][0] = oper[6];
									expression[9][1] = eOperator;
									expression[0][0] = oper[4];
									expression[0][1] = eOperator;
									expression[6][0] = oper[5];
									expression[6][1] = eOperator;									
									dRes = CalcOneExpress(expression);
									if(Equal24(dRes))
									{
										printf("可以这样运算:%c%d%c%d%c%d%c%c%d\n",oper[4],expression[1][0],oper[ii],expression[3][0],oper[jj],expression[5][0],oper[5],oper[kk],expression[8][0]);
										return TRUE;
										
									}								
							}
						}
					}//end of for oper
				}
			}
		}
	}

	return FALSE;
}

int CalcArray4(int iNumInput[2][4])
{
	// (a * b * c) * d	//9 number
	int expression[10][2];
	int ii,jj,i,j,k,l,kk;
	int dRes;
//	printf("CalcArray4\n");
    for(i=0;i<4;i++)
    {
        for(j=0;j<4;j++)    
        {
            if(j==i)
            {
                continue;
            }
            for(k=0;k<4;k++)
            {
                if(k==i||k==j)
                {
                    continue;
                }
                for(l=0;l<4;l++)
                {
                    if(l==i||l==j||l==k)
                    {
                        continue;
                    }
                    expression[0][0]=iNumInput[0][i];
                    expression[3][0]=iNumInput[0][j];
                    expression[5][0]=iNumInput[0][k];
                    expression[8][0]=iNumInput[0][l];

					expression[0][1]=eNumber;
					expression[3][1]=eNumber;
					expression[5][1]=eNumber;
					expression[8][1]=eNumber;
					for (ii=0;ii<4;ii++)
					{
						for (jj=0;jj<4;jj++)
						{
							for (kk=0;kk<4;kk++)
							{

									expression[1][0] = oper[ii];
									expression[1][1] = eOperator;
									expression[4][0] = oper[jj];
									expression[4][1] = eOperator;
									expression[7][0] = oper[kk];
									expression[7][1] = eOperator;
									expression[9][0] = oper[6];
									expression[9][1] = eOperator;
									expression[2][0] = oper[4];
									expression[2][1] = eOperator;
									expression[6][0] = oper[5];
									expression[6][1] = eOperator;
									
									dRes = CalcOneExpress(expression);
									if(Equal24(dRes))
									{
										printf("可以这样运算:%d%c%c%d%c%d%c%c%d\n",expression[0][0],oper[ii],oper[4],expression[3][0],oper[jj],expression[5][0],oper[5],oper[kk],expression[8][0]);
										return TRUE;
										
									}								
							}
						}
					}//end of for oper
				}
			}
		}
	}

	return FALSE;
}


int CalcArray5(int iNumInput[2][4])
{
	// (a * b) * (c * d)	//11 number
	int expression[12][2];
	int ii,jj,i,j,k,l,kk;
	int dRes;
//	printf("CalcArray5\n");
    for(i=0;i<4;i++)
    {
        for(j=0;j<4;j++)    
        {
            if(j==i)

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