triangulate_test.m

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% Test the code using the dag in Fig 1 of Jensen, Jensen, Dittmer, % "From influence diagrams to junction trees", UAI 94% By reverse enginering Fig 2, we infer that the following arcs should% be absent from the original dag:  b->d1, e->d2, f->d2, g->d4a=1; b=2; d1=3; c=4; d=5; e=6; f=7; g=8; d2=9; d4=10; i=11; h=12; d3=13; l=14; j=15; k=16;dag=zeros(16);dag(a,c)=1;%dag(b,[c d d1])=1;dag(b,[c d])=1;dag(d1,d)=1;dag(c,e)=1;dag(d,[e f])=1;%dag(e,[g d2])=1;dag(e,[g])=1;%dag(f,[d2 h])=1;dag(f,[h])=1;%dag(g,[d4 i])=1;dag(g,[i])=1;dag(d2,i)=1;dag(d4,l)=1;dag(i,l)=1;dag(h,[j k])=1;dag(d3,k)=1;[MG, moral_edges] = moralize(dag);MG(j,k)=1; MG(k,j)=1;  % simulate having a common utility child% MG now equals fig 2order = [l j k i h a c d d4 g d3 d2 f e d1 b];[MTG, cliques, fill_ins] = triangulate(MG, order);% MTG equals fig 3ns = 2*ones(1,16);[jtree, root, cliques2] = mk_strong_jtree(cliques, ns, order, MTG);jtree2 = mk_rooted_tree(jtree, root);% jtree2 equals fig 4, with their arrows reversed

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