minimum_spanning_tree.m
来自「麻省理工学院的人工智能工具箱,很珍贵,希望对大家有用!」· M 代码 · 共 52 行
M
52 行
function A = minimum_spanning_tree(C1, C2)%% Find the minimum spanning tree using Prim's algorithm.% C1(i,j) is the primary cost of connecting i to j.% C2(i,j) is the (optional) secondary cost of connecting i to j, used to break ties.% We assume that absent edges have 0 cost.% To find the maximum spanning tree, used -1*C.% See Aho, Hopcroft & Ullman 1983, "Data structures and algorithms", p 237.% Prim's is O(V^2). Kruskal's algorithm is O(E log E) and hence is more efficient% for sparse graphs, but is implemented in terms of a priority queue.% We partition the nodes into those in U and those not in U.% closest(i) is the vertex in U that is closest to i in V-U.% lowcost(i) is the cost of the edge (i, closest(i)), or infinity is i has been used.% In Aho, they say C(i,j) should be "some appropriate large value" if the edge is missing.% We set it to infinity.% However, since lowcost is initialized from C, we must distinguish absent edges from used nodes.n = length(C1);if nargin==1, C2 = zeros(n); endA = zeros(n);closest = ones(1,n);used = zeros(1,n); % contains the members of Uused(1) = 1; % start with node 1C1(find(C1==0))=inf;C2(find(C2==0))=inf;lowcost1 = C1(1,:);lowcost2 = C2(1,:);for i=2:n ks = find(lowcost1==min(lowcost1)); k = ks(argmin(lowcost2(ks))); A(k, closest(k)) = 1; A(closest(k), k) = 1; lowcost1(k) = inf; lowcost2(k) = inf; used(k) = 1; NU = find(used==0); for ji=1:length(NU) for j=NU(ji) if C1(k,j) < lowcost1(j) lowcost1(j) = C1(k,j); lowcost2(j) = C2(k,j); closest(j) = k; end end endend
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?