int.c
来自「君正早期ucos系统(只有早期的才不没有打包成库),MPLAYER,文件系统,图」· C语言 代码 · 共 88 行
C
88 行
/* * Copyright (c) 2001-2002, David Janssens * All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS `AS IS' * AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE * LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR * CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF * SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS * INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN * CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) * ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE * POSSIBILITY OF SUCH DAMAGE. *//// <summary>/// Get the minimum of two integers./// </summary>int int_min(int a, int b) { return a<b?a:b;}/// <summary>/// Get the maximum of two integers./// </summary>int int_max(int a, int b) { return a>b?a:b;}/// <summary>/// Clamp an integer inside an interval./// </summary>int int_clamp(int a, int min, int max) { if (a<min) return min; if (a>max) return max; return a;}/// <summary>/// Get absolute value of integer./// </summary>int int_abs(int a) { return a<0?-a:a;}/// <summary>/// Divide an integer and round upwards./// </summary>int int_ceildiv(int a, int b) { return (a+b-1)/b;}/// <summary>/// Divide an integer by a power of 2 and round upwards./// </summary>int int_ceildivpow2(int a, int b) { return (a+(1<<b)-1)>>b;}/// <summary>/// Divide an integer by a power of 2 and round downwards./// </summary>int int_floordivpow2(int a, int b) { return a>>b;}/// <summary>/// Get logarithm of an integer and round downwards./// </summary>int int_floorlog2(int a) { int l; for (l=0; a>1; l++) { a>>=1; } return l;}
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