📄 dfp2.m
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%DFP计算算法(不精确一维搜索,k=27,mul_count=2326,sum_count=1462,花费时间很少)
syms x1 x2;
f=50*(x2-x1^2)^2+(1-x1)^2;
v=[x1,x2];
df=jacobian(f,v);
df=df.';
epson=1e-12;x0=[0,0]';g1=subs(df,{x1,x2},{x0(1,1),x0(2,1)});k=0;H0=[1,0;0,1];mul_count=0;sum_count=0;
mul_count=mul_count+7;sum_count=sum_count+4;
while(norm(g1)>epson&k<1000)
mul_count=mul_count+2;sum_count=sum_count+1;
if k==0
p=-H0*g1;mul_count=mul_count+7;sum_count=sum_count+4;
else
H1=H0-H0*yk*yk'*H0/(yk'*H0*yk)+sk*sk'/(yk'*sk);mul_count=mul_count+36;sum_count=sum_count+18;
p=-H1*g1;mul_count=mul_count+7;sum_count=sum_count+4;
H0=H1;
end
x00=x0;
result=Usearch1(f,x1,x2,df,x0,p);
arf=result(1);Mul=result(2);Sum=result(3);
mul_count=mul_count+Mul;sum_count=sum_count+Sum;
x0=x0+arf*p;
g0=g1;
g1=subs(df,{x1,x2},{x0(1,1),x0(2,1)});
p0=p;
yk=g1-g0; sk=x0-x00;
k=k+1;
mul_count=mul_count+9;sum_count=sum_count+11;
end;
k
x0
mul_count
sum_count
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