📄 prp1.m
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%PRP直接计算降法(精确一维搜索,k=19,mul_count=8390,sum_count=3745,花费时间很少)
syms x1 x2 ar;
f=50*(x2-x1^2)^2+(1-x1)^2;
v=[x1,x2];
df=jacobian(f,v);
df=df.';
epson=1e-12;x0=[0,0]';g1=subs(df,{x1,x2},{x0(1,1),x0(2,1)});k=0;mul_count=0;sum_count=0;
mul_count=mul_count+7;sum_count=sum_count+4;
while(norm(g1)>epson)
mul_count=mul_count+2;sum_count=sum_count+1;
if k==0
p=-g1;
else
bta=(g1'*(g1-g0))/(g0'*g0);
p=-g1+bta*p0;
mul_count=mul_count+7;sum_count=sum_count+6;
end
y=subs(f,{x1,x2},{x0(1,1)+ar*p(1,1),x0(2,1)+ar*p(2,1)});mul_count=mul_count+18;sum_count=sum_count+12;
result1=qujian(y,ar);
b1=result1(1);mul_count=mul_count+result1(2);sum_count=sum_count+result1(3);
result2=Asearch(y,ar,b1);
arf=result2(1);mul_count=mul_count+result2(2);sum_count=sum_count+result2(3);
x0=x0+arf*p;
g0=g1;
g1=subs(df,{x1,x2},{x0(1,1),x0(2,1)});
p0=p;
k=k+1;
mul_count=mul_count+9;sum_count=sum_count+7;
end;
k
x0
mul_count
sum_count
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