📄 2.txt
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这只是我的工作总结，其实也算是刚刚搞J2EE吧，所以还算是个新手，可从来都懒的写文章的，现在回头想象总结原来是如此的重要， 本文主要描述的是eclipse下整合struts。其实网上这样的文章不知道有多少，但还是希望有兴趣的朋友不仿看看，要是发现有不好的地方的话恳请指正，谢谢！（环境：windows xp+tomcat5.5.28+jdk6+eclipse3.3+myeclipse6）
1 打开eclipse，新建web project。
2 整合struts，右击项目选择myeclipse下的add struts Capabilities。
3 创建一个名为LoginActionForm的ActionForm文件，如下图：
LoginActionForm.java 源代码如下：
/** *//**
*Copyright 2008, CSSWEB all rights reserved.
*@author hujun
*@date Mar 21, 2008
*@file LoginActionForm.java
*@version 1.1
**/
package css.web.orc.form;
import org.apache.struts.action.ActionForm;
public class LoginActionForm extends ActionForm...{
private static final long serialVersionUID = 1L;
private String userid;
private String passwd;
private String msg;
public String getUserid() ...{
return userid;
}
public void setUserid(String userid) ...{
this.userid = userid;
}
public String getPasswd() ...{
return passwd;
}
public void setPasswd(String passwd) ...{
this.passwd = passwd;
}
public String getMsg() ...{
return msg;
}
public void setMsg(String msg) ...{
this.msg = msg;
}
}
在init下创建一个名为LoginAction的Action文件，如下：
/** *//**
*Copyright 2008, CSSWEB all rights reserved.
*@author hujun
*@date Mar 21, 2008
*@file LoginAction.java
*@version 1.1
**/
package css.web.orc.action.init;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import css.web.orc.form.LoginActionForm;
public class LoginAction extends Action...{
public ActionForward execute(ActionMapping mapping,ActionForm form,
HttpServletRequest request,HttpServletResponse response) ...{
String forward = "";
try
...{
LoginActionForm loginform = (LoginActionForm)form;
String userid = "";
String passwd = "";
userid = loginform.getUserid();
passwd = loginform.getPasswd();
if(userid.equals("hujun")&&passwd.equals("123456")) ...{
forward = "main";
}
else ...{
forward = "login";
loginform.setMsg("您输入的用户名和密码不正确!");
}
}
catch (Exception e) ...{
e.printStackTrace();
}
return mapping.findForward(forward);
}
}
4 接下来要在webroot下建两个.jsp文件，分别是login.jsp和main.jsp，代码如下：
<%...@ page language="java"%>
<%...@ page contentType="text/html;charset=GBK" %>
<%...@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean" %>
<%...@ taglib uri="/WEB-INF/struts-html.tld" prefix="html" %>
<%...@ taglib uri="/WEB-INF/struts-logic.tld" prefix="logic" %>
<html>
<title>首页</title>
<body>
<html:form action="/init/LoginAction.do" method="post">
<br><br><br><br><br><br>
<table width="50%" align="center" border="0">
<tr>
<td width="100%" align="left">
<font size="2" color="red">
<b><bean:write name="LoginActionForm" property="msg" /></b>
</font></td>
</tr>
</table>
<table width="50%" align="center" border="1">
<tr>
<td width="30%" align="right">用户名:</td>
<td width="70%" align="left">
<html:text property="userid" maxlength="15"></html:text>
</td>
</tr>
<tr>
<td width="30%" align="right">密码:</td>
<td width="70%" align="left">
<html:text property="passwd" maxlength="30"></html:text>
</td>
</tr>
</table>
<table width="50%" align="center" border="0">
<tr>
<td width="50%" align="right"><html:submit value="确认" /></td>
<td width="50%" align="left"> <html:reset value="重置" /></td>
</tr>
</table>
</html:form>
</body>
</html>
<%...@ page language="java"%>
<%...@ page contentType="text/html;charset=GBK" %>
<%...@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean" %>
<%...@ taglib uri="/WEB-INF/struts-html.tld" prefix="html" %>
<%...@ taglib uri="/WEB-INF/struts-logic.tld" prefix="logic" %>
<html>
<title>首页</title>
<body>
<html:form action="/init/LoginAction" method="post">
<br><br><br><br><br>
<table width="50%" align="center" border="0">
<tr>
<td width="100%" align="left"><font size="5" color="blue"><b>
欢迎您,<bean:write name="LoginActionForm" property="userid"></bean:write>
</b></font></td>
</tr>
</table>
</html:form>
</body>
</html>
5 web.xml文件如下：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>3</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>3</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>/init/login.jsp</welcome-file>
</welcome-file-list>
</web-app>
6 struts-config.xml文件如下：
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.1//EN" "http://jakarta.apache.org/struts/dtds/struts-config_1_1.dtd">
<struts-config>
<form-beans>
<form-bean name="LoginActionForm" type="css.web.orc.form.LoginActionForm"></form-bean>
</form-beans>
<global-forwards>
<forward name="error" path="init/errPage.jsp"></forward>
</global-forwards>
<action-mappings>
<action name="LoginActionForm" type="css.web.orc.action.init.LoginAction" scope="request" path="/init/LoginAction">
<forward name="main" path="/init/main.jsp"></forward>
<forward name="login" path="/init/login.jsp"></forward>
</action>
</action-mappings>
</struts-config>
7 将项目部署到tomcat下：
8 好了，接下来运行tomcat，然后在浏览器里输入地址，运行即可。
文章出处：http://www.diybl.com/course/3_program/java/javashl/2008321/105948.html⌨️ 快捷键说明
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