07-36.txt

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例7-36  使用linsolve函数求解符号线性方程组。
解：在命令窗口中输入如下命令，并按Enter键确认。
>> a=sym('rand(5)')
a =
 rand(5)
>> b=('[1;2;3;4;5]')
b =
 [1;2;3;4;5]
>> linsolve(a,b)
ans =
[ 1/proc () local t; global _seed; _seed := irem(427419669081*_seed,999999999989); t := _seed; irem(t,5) end]
[ 2/proc () local t; global _seed; _seed := irem(427419669081*_seed,999999999989); t := _seed; irem(t,5) end]
[ 3/proc () local t; global _seed; _seed := irem(427419669081*_seed,999999999989); t := _seed; irem(t,5) end]
[ 4/proc () local t; global _seed; _seed := irem(427419669081*_seed,999999999989); t := _seed; irem(t,5) end]
[ 5/proc () local t; global _seed; _seed := irem(427419669081*_seed,999999999989); t := _seed; irem(t,5) end]
>>