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\section{THEORETICAL DEFINITION OF A STACKING OPERATOR}%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%In practice, integration of discrete data is performed by stacking.In theory, it is convenient torepresent a stacking operator in the form of a continuous integral:\begin{equation}S(t,y)= {\bf A}\left[M(z,x)\right]= \int\limits_{\Omega} w(x;t,y)\,M(\theta(x;t,y),x)\,dx\;.\label{eqn:operator}\end{equation} Function $M(z,x)$ is the input of the operator, $S(t,y)$ is theoutput, $\Omega$ is the summation aperture, $\theta$ represents the summation path, and $w$ stands for theweighting function. The range of integration (theoperator aperture) may also depend on $t$ and $y$. Allowing $x$ to bea two-dimensional variable, we can use definition (\ref{eqn:operator}) torepresent an operator applied to three-dimensional data. Throughoutthis paper, I assume that $t$ and $z$ belong to a one-dimensionalspace, and that $x$ and $y$ have the same number of dimensions.\parThe goal of inversion is to reconstruct some function$\widehat{M}(z,x)$ for a given $S(t,y)$, so that $\widehat{M}$ is in some sense close to $M$ in equation (\ref{eqn:operator}).
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