1302 the snail.cpp

威士忌的HDU题解.大概有260多题的源码。对于学习非常有好处。

#include <cstdio>
using namespace std;
int h,u,d,f;
double now,up,rate;

int main()
{
	int day;
	
	while( scanf("%d %d %d %d",&h,&u,&d,&f)!=EOF && h)
	{
		now=0;up=u;rate=(double)f/100 * u;
		for(day=1; 1 ; day++)
		{
			now+= up;
			if(now>h)
				break;
			now-= d; 
			if(now<0)
				break;
			up-=rate;
			if(up<0)//注意up不为负 
				up=0;
		}
		if(now>=h)
			printf("success on day %d\n",day);
		else
			printf("failure on day %d\n",day);
	}
	return 0;
}