ex6_6.m

来自「美国 A.E.Fitgerald著 刘新正,苏少平,高琳翻译,第六版的源代码」· M 代码 · 共 56 行

% Example 6.6

clc
clear

% Here are the two sets of parameters

R1(1) = 0.262;          R1(2) = 0.262;
R2(1) = 0.447;          R2(2) = 0.444;
X1(1) = 0.633;           X1(2) = 0.603;
X2(1) = 1.47;           X2(2) = 1.41;
Xm(1) = 21.2;           Xm(2) = 21.2;

Nph = 3;
poles = 4;
Prot = 354;

%Here is the operating condition

V1 = 220/sqrt(3);
fe = 60;
rpm = 1746;

%Calculate the synchronous speed

ns = 120*fe/poles;
omegas = 4*pi*fe/poles;

slip = (ns-rpm)/ns;
omegam = omegas*(1-slip);

%Calculate stator Thevenin equivalent

%Loop over the two motors
for m = 1:2

Zgap = j*Xm(m)*(j*X2(m)+R2(m)/slip)/(R2(m)/slip+j*(Xm(m)+X2(m)));
Zin = R1(m) + j*X1(m) + Zgap;   
I1 = V1/Zin;
I2 = I1*(j*Xm(m))/(R2(m)/slip+j*(Xm(m)+X2(m)));
Tmech = Nph*abs(I2)^2*R2(m)/(slip*omegas);  %Internal torque
Pmech = omegam*Tmech;		  %Internal power
Pshaft = Pmech - Prot;

if (m == 1)
	fprintf('\nFor parameters of Example 7-5:')
else 
	fprintf('\nFor parameters of Example 7-6(a):')
end

fprintf('\n   Pmech = %.1f [W], Pshaft = %.1f [W]',Pmech,Pshaft)
fprintf('\n   I1 = %.1f [A]\n',abs(I1));  


end % end of "for m = 1:2" loop