📄 matlab记录满足要求的点并画这些点的等高线.htm
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id="content_inner"> <DIV class="mb12 bai"><DIV class="rg_1"></DIV><DIV class="rg_2"></DIV><DIV class="rg_3"></DIV><DIV class="rg"><DIV class="t1" id="question_status"><SPAN style="float:right;padding-right:10px;font-size:12px;font-weight:normal;margin-top:-1px;"><SPAN class="ico"><SPAN class="irelate"> </SPAN></SPAN><A href="http://zhidao.baidu.com/question/68962030.html?fr=qrl#irelatelink" class="lbk">相关问题</A></SPAN><SPAN style="width:100px;float:right;font-size:12px;font-weight:normal"><DIV class="icosc"></DIV> <A href="http://cang.baidu.com/do/add" onclick="window.open('http://cang.baidu.com/do/add?it='+encodeURIComponent(document.title)+'&iu='+encodeURIComponent(location.href)+'&tn=%E7%9F%A5%E9%81%93%E9%97%AE%E9%A2%98%2C&fr=ik#nw=1','_s','scrollbars=no,width=600,height=450,right=75,top=20,status=no,resizable=yes'); return false;" target="_blank" class="lbk">添加到搜藏</A></SPAN><DIV class="ico"><DIV class="iok"></DIV></DIV>已解决 </DIV><DIV class="bc0"><DIV class="p90"><DIV class="f14 B wr" id="question_title"> <CQ>matlab记录满足要求的点并画这些点的等高线</CQ></DIV><DIV class="wr" id="question_info"><SPAN class="red"><IMG src="./matlab记录满足要求的点并画这些点的等高线_files/icn_point.gif" width="16" height="16" align="absmiddle"> 悬赏分：200</SPAN> - <SPAN class="gray">解决时间：2008-9-20 16:07</SPAN></DIV><DIV class="f14 wr" id="question_content"><CD>程序思路（举个例子）：在-20<y<20,-20<z<20,范围内搜索点，判断如果<BR>y^2+z^2<100;则记录下此点，x=abs(y)+abs(z);将这些点保存在矩阵或树组中都可以，总之要记录下来，最后画y,z关于x的等高线图（要平面图，就是一圈一圈那种），请帮忙设计个类似的能通用的程序，搜索y,z要循环嵌套循环，满足的点放到数组或矩阵里，不满足继续搜索。如果答案采纳再追加200分（总之把我的分都给你），谢谢！</CD></DIV><DIV class="f14 wr" id="question_sup"><B>问题补充：</B>感谢 wacs5，你的程序可以实现，但我实际的程序很大，判断如果 y^2+z^2<100；这句能否用if语句，否则在我的程序中不容易实现，find和NaN我不是很熟悉能解释一下吗？再次谢谢<BR>这是我程序的一部分：<BR>e=-60:1:60;<BR>f=-150:1:150;<BR>for i=1:length(e)<BR>for j=1:length(f)<BR> 中间计算过程<BR> if 判断是否满足要求<BR> 满足则记录e与f<BR> 然后画y,z关于x的等高线图，<BR>还有就是contour（*，*，*，*）我也不是很会用，<BR>最后一个数代表什么？</DIV></DIV><DIV align="right" class="gray wr" id="question_author">提问者： <A href="http://passport.baidu.com/?business&aid=6&un=zhaoyuming992#2" target="_blank">zhaoyuming992</A> - <A href="http://www.baidu.com/search/zhidao_help.html#n5" target="_blank">助理 二级</A> </DIV></DIV></DIV><DIV class="rg_4"></DIV><DIV class="rg_5"></DIV><DIV class="rg_1"></DIV></DIV><DIV class="mb12 bai"><DIV class="rr_1"></DIV><DIV class="rr_2"></DIV><DIV class="rr_3"></DIV><DIV class="rr"><DIV class="t1"><DIV class="ico"><DIV class="ibest"></DIV></DIV>最佳答案</DIV><DIV class="bc0" style="padding:5px 0pt;"><DIV class="wr"> <DIV class="f14 p90 pl10" id="best_answer_content"> <CA>y=-20:0.1:20; <BR>z=-20:0.1:20; <BR>[yy,zz]=meshgrid(y,z); <BR>x=abs(yy)+abs(zz); <BR><BR>i=find(yy.^2+zz.^2>=100); <BR>x(i)=NaN; <BR>contour(yy,zz,x,15); <BR><BR>=============for循环实现============= <BR>y=-20:0.2:20; <BR>z=-20:0.5:20; <BR>[yy,zz]=meshgrid(y,z); <BR><BR>[ny,nz]=size(yy); <BR>x=zeros(size(yy)); <BR>flag=[]; <BR>num=1; <BR>for i=1:ny <BR>for j=1:nz <BR>if yy(i,j)^2+zz(i,j)^2<100 %记录下满足条件的点的横纵标号 <BR>flag(1,num)=i; <BR>flag(2,num)=j; <BR>x(i,j)=NAN; %不满足的点,还是赋值NAN,你赋别的话,做等高线的时候会有一点小问题 <BR>num=num+1; <BR>else <BR>x(i,j)=abs(yy(i,j))+abs(zz(i,j)); <BR>end <BR>end <BR>end <BR>contour(yy,zz,x,15); <BR><BR>我还没有实验过。<BR><BR>==================<BR>coutour最后一个代表画等高线的条数。</CA></DIV><DIV align="right" class="gray" style="margin:5px;" id="best_answer_info"> 回答者：<A href="http://passport.baidu.com/?business&aid=6&un=wacs5#2" target="_blank">wacs5</A> -<A href="http://www.baidu.com/search/zhidao_help.html#n5" target="_blank"> 副总裁 十一级</A><SPAN id="im-user-5dbc7761637335e901" title="wacs5"> <IMG style="cursor: pointer;" align="absbottom" onclick="startBaiduHi("message","","wacs5",{clk:"icon",src:"zhidao"});return false;" src="./matlab记录满足要求的点并画这些点的等高线_files/offline.gif"></SPAN> <SPAN id="best_answer_time">9-20 15:25</SPAN></DIV><DIV style="text-align:right;margin:5px;"><A href="http://zhidao.baidu.com/q?ct=20&qid=68962030&cm=6&tn=ikqbremark&mrn=25" target="_blank">查看用户评论(1)>> </A></DIV><DIV class="t2">提问者对于答案的评价：</DIV><DIV class="p90 pl10 f14" id="best_answer_comment">程序运行出来了，我的也调试完毕，非常感谢！！！<BR>这么短的时间就编出了程序，不愧为高手！！</DIV><DIV class="t2">您觉得最佳答案好不好？ <SPAN class="f12 gray" style="font-weight:normal">目前有 0 个人评价</SPAN></DIV><DIV class="pl10"><FORM method="post" name="fpj" action="http://zhidao.baidu.com/q"><INPUT type="hidden" name="ct" value="22"><INPUT type="hidden" name="mpn"><INPUT type="hidden" name="cm" value="100003"><INPUT type="hidden" name="qid" value="68962030"><INPUT type="hidden" name="tn" value="iksubmit"><INPUT type="hidden" name="lu" value="http%3A//zhidao.baidu.com/question/68962030.html%3Ffr%3Dqrl"><TABLE border="0" cellpadding="0" cellspacing="0"><TBODY><TR valign="top"><SCRIPT>function g(w){ document.fpj.mpn.value=w;};document.fpj.lu.value=escape(location.href)</SCRIPT><TD width="120" class="f14"><INPUT type="button" onclick="g(1);checkLoginF(JudgeBestAnswer,'vote_good');" value="好" class="bn100" id="good_4_best_answer"><BR><SPAN class="red">50%</SPAN> 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