📄 matlab 做等高线的问题.htm
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</DIV> <DIV id="path"><A href="http://zhidao.baidu.com/">百度知道</A> > <CC><A href="http://zhidao.baidu.com/browse/202?lm=2">理工学科</A> > <A href="http://zhidao.baidu.com/browse/983?lm=2">数学</A></CC></DIV><DIV id="content"><DIV id="content_inner"> <DIV class="mb12 bai"><DIV class="rg_1"></DIV><DIV class="rg_2"></DIV><DIV class="rg_3"></DIV><DIV class="rg"><DIV class="t1" id="question_status"><SPAN style="float:right;padding-right:10px;font-size:12px;font-weight:normal;margin-top:-1px;"><SPAN class="ico"><SPAN class="irelate"> </SPAN></SPAN><A href="http://zhidao.baidu.com/question/50889822.html?fr=qrl#irelatelink" class="lbk">相关问题</A></SPAN><SPAN style="width:100px;float:right;font-size:12px;font-weight:normal"><DIV class="icosc"></DIV> <A href="http://cang.baidu.com/do/add" onclick="window.open('http://cang.baidu.com/do/add?it='+encodeURIComponent(document.title)+'&iu='+encodeURIComponent(location.href)+'&tn=%E7%9F%A5%E9%81%93%E9%97%AE%E9%A2%98%2C&fr=ik#nw=1','_s','scrollbars=no,width=600,height=450,right=75,top=20,status=no,resizable=yes'); return false;" target="_blank" class="lbk">添加到搜藏</A></SPAN><DIV class="ico"><DIV class="iok"></DIV></DIV>已解决 </DIV><DIV class="bc0"><DIV class="p90"><DIV class="f14 B wr" id="question_title"> <CQ>matlab 做等高线的问题,函数已知</CQ></DIV><DIV class="wr" id="question_info"><SPAN class="red"><IMG src="./matlab 做等高线的问题_files/icn_point.gif" width="16" height="16" align="absmiddle"> 悬赏分：20</SPAN> - <SPAN class="gray">解决时间：2008-4-13 01:08</SPAN></DIV><DIV class="f14 wr" id="question_content"><CD>求教高手关于我遇到一个问题,如何做等高线的问题,如下: <BR><BR>e='10000/(15.3608*x^2-1.5259*y^3+33.4642*y^2-65.9564*y+10000/127)' <BR>subplot(2,1,1) <BR>ezsurf(e,[-16,16,0,16]) <BR>title('Ez=10000/(15.3608x^2-1.5259y^3+33.4642y^2-65.9564y+78.7402)') <BR>subplot(2,1,2) <BR><BR><BR>图2我想画 10:10:120 的等高线，请问该如何写代码？谢谢啦~~</CD></DIV><DIV class="f14 wr" id="question_sup"></DIV></DIV><DIV align="right" class="gray wr" id="question_author">提问者： <A href="http://passport.baidu.com/?business&aid=6&un=sum456#2" target="_blank">sum456</A> - <A href="http://www.baidu.com/search/zhidao_help.html#n5" target="_blank">见习魔法师 二级</A> </DIV></DIV></DIV><DIV class="rg_4"></DIV><DIV class="rg_5"></DIV><DIV class="rg_1"></DIV></DIV><DIV class="mb12 bai"><DIV class="rr_1"></DIV><DIV class="rr_2"></DIV><DIV class="rr_3"></DIV><DIV class="rr"><DIV class="t1"><DIV class="ico"><DIV class="ibest"></DIV></DIV>最佳答案</DIV><DIV class="bc0" style="padding:5px 0pt;"><DIV class="wr"> <DIV class="f14 p90 pl10" id="best_answer_content"> <CA>e='10000/(15.3608*x^2-1.5259*y^3+33.4642*y^2-65.9564*y+10000/127)' <BR>subplot(2,1,1) <BR>ezsurfc(e,[-16,16,0,16]) <BR>title('Ez=10000/(15.3608x^2-1.5259y^3+33.4642y^2-65.9564y+78.7402)') <BR>subplot(2,1,2) <BR>ezcontour(e,[-16,16,0,16])</CA></DIV><DIV align="right" class="gray" style="margin:5px;" id="best_answer_info"> 回答者：<A href="http://passport.baidu.com/?business&aid=6&un=%BB%AF%D1%A7%B9%A4%B3%CC#2" target="_blank">化学工程</A> -<A href="http://www.baidu.com/search/zhidao_help.html#n5" target="_blank"> 首席运营官 十三级</A><SPAN id="im-user-4777bbafd1a7b9a4b3ccd500" title="化学工程"> <IMG style="cursor: pointer;" align="absbottom" onclick="startBaiduHi("message","","化学工程",{clk:"icon",src:"zhidao"});return false;" src="./matlab 做等高线的问题_files/offline.gif"></SPAN> <SPAN id="best_answer_time">4-12 22:10</SPAN></DIV><DIV style="text-align:right;margin:5px;"><A href="http://zhidao.baidu.com/q?ct=20&qid=50889822&cm=6&tn=ikqbremark&mrn=25" target="_blank">我来评论>></A></DIV><DIV class="t2">提问者对于答案的评价：</DIV><DIV class="p90 pl10 f14" id="best_answer_comment">太感谢您了！<BR>另外，该区域内的max(e)及其相应的x,y坐标能求么？</DIV><DIV class="t2">评价已经被关闭 <SPAN class="f12 gray" style="font-weight:normal">目前有 0 个人评价</SPAN></DIV><DIV class="pl10"><FORM method="post" name="fpj" 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