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📄 sunrise.m

📁 一个计算海天背景的工程模型。由matlab编写
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function [rhr,rmin,shr,smin]=sunrise(mon,da,yr,lat,long)

% SUNRISE: computes sunrise and sunset times for specified day and location. 

% [rhr,rmin,shr,smin] = SUNRISE(mon,da,yr,lat,long) computes the time 

% of sunrise rhr:rmin and sunset shr:smin to the nearest minute in GMT 

% for a calendar day(s) and a specified (scalar) position.   

% 

% INPUT:  mon - month (e.g., Jan is 1)

%         da - day (e.g., Jan 10th is 10)

%         yr - year (e.g., 1995)

%         lat - latitude [deg]

%         long - longitude (west is positive)  [deg] 

%

% OUTPUT: rhr,rmin  - sunrise in GMT hours and minutes

%          shr,smin  - sunset in GMT hours and minutes.



%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% 8/28/98: version 1.1 (contributed by RP)

% 8/5/99: version 2.0

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%



% convert calender time to julian yd

j=julianmd(yr,mon,da,0);

j0=julianmd(yr,1,1,0);

yd=j(:)-j0(:);



% compute solar altitude for entire day

dt=1./2880;



% we don't want abs(long)>180...

if long<-180, long=long+360; end;

if long>180,  long=long-360; end;



time=dt.*[0:2879]'+long/360; % have a whole day, beginning at midnight (near enough)

yday=yd(ones(1,2880),:)+time(:,ones(length(yd),1));



if length(yr)>1,

  yr=yr(:,ones(1,2880))';

end;



[z,sorad]=soradna1(yday(:),yr(:),long,lat);



z=reshape(z,2880,length(yd));

sorad=reshape(sorad,2880,length(yd));



[ir,jr]=find(sorad(1:2879,:)==0 & sorad(2:2880,:)>0);

[is,js]=find(sorad(2:2880,:)==0 & sorad(1:2879,:)>0);



srise=zeros(length(yd),1);

sset=any(sorad>0);



srise(jr)=yday(ir+(jr-1)*2880);

sset(js) =yday(is+(js-1)*2880);



rhr=fix(rem(srise,1)*24);

rmin=rem(rem(srise,1)*1440,60);

shr=fix(rem(sset,1)*24);

smin=rem(rem(sset,1)*1440,60);









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