⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 data.java

📁 tinyos2.0版本驱动
💻 JAVA
字号:
/* * Copyright (c) 2006 Intel Corporation * All rights reserved. * * This file is distributed under the terms in the attached INTEL-LICENSE      * file. If you do not find these files, copies can be found by writing to * Intel Research Berkeley, 2150 Shattuck Avenue, Suite 1300, Berkeley, CA,  * 94704.  Attention:  Intel License Inquiry. */import java.util.*;/* Hold all data received from motes */class Data {    /* The mote data is stored in a flat array indexed by a mote's identifier.       A null value indicates no mote with that identifier. */    private Node[] nodes = new Node[256];    private Oscilloscope parent;    Data(Oscilloscope parent) {    this.parent = parent;    }    /* Data received from mote nodeId containing NREADINGS samples from       messageId * NREADINGS onwards. Tell parent if this is a new node. */    void update(int nodeId, int messageId, int readings[]) {    if (nodeId >= nodes.length) {        int newLength = nodes.length * 2;        if (nodeId >= newLength) {            newLength = nodeId + 1;        }        Node newNodes[] = new Node[newLength];        System.arraycopy(nodes, 0, newNodes, 0, nodes.length);        nodes = newNodes;    }    Node node = nodes[nodeId];    if (node == null) {        nodes[nodeId] = node = new Node(nodeId);        parent.newNode(nodeId);    }    node.update(messageId, readings);    }    /* Return value of sample x for mote nodeId, or -1 for missing data */    int getData(int nodeId, int x) {    if (nodeId >= nodes.length || nodes[nodeId] == null)        return -1;    return nodes[nodeId].getData(x);    }    /* Return number of last known sample on mote nodeId. Returns 0 for       unknown motes. */    int maxX(int nodeId) {    if (nodeId >= nodes.length || nodes[nodeId] == null)        return 0;    return nodes[nodeId].maxX();    }    /* Return number of largest known sample on all motes (0 if there are no       motes) */    int maxX() {    int max = 0;    for (int i = 0; i < nodes.length; i++) {        if (nodes[i] != null) {        int nmax = nodes[i].maxX();        if (nmax > max)            max = nmax;        }    }    return max;    }}

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -