📄 objecttocountermap.java
字号:
/* * LingPipe v. 3.5 * Copyright (C) 2003-2008 Alias-i * * This program is licensed under the Alias-i Royalty Free License * Version 1 WITHOUT ANY WARRANTY, without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the Alias-i * Royalty Free License Version 1 for more details. * * You should have received a copy of the Alias-i Royalty Free License * Version 1 along with this program; if not, visit * http://alias-i.com/lingpipe/licenses/lingpipe-license-1.txt or contact * Alias-i, Inc. at 181 North 11th Street, Suite 401, Brooklyn, NY 11211, * +1 (718) 290-9170. */package com.aliasi.util;import java.util.Arrays;import java.util.Comparator;import java.util.Collections;import java.util.HashMap;import java.util.Iterator;import java.util.List;import java.util.Map;import java.util.Set;import java.util.ArrayList;/** * An <code>ObjectToCounterMap</code> maintains a mapping from objects * to integer counters, which may be incremented or set. Objects not * in the underlying map are assumed to have count <code>0</code>, so * that incrementing an object that is not mapped sets it to the * increment amount. * * @author Bob Carpenter * @version 3.1.1 * @since LingPipe1.0 */public class ObjectToCounterMap<E> extends HashMap<E,Counter> { // inherits serializability from parent HashMap static final long serialVersionUID = -4735380145915633564L; /** * Construct an object to counter mapping. */ public ObjectToCounterMap() { /* do nothing */ } /** * Increment the value of the specified key by <code>1</code>. * Removes the key from the underlying map if the value after * incrementing is <code>0</code>. Sets the value of the key to * <code>1</code> if it is not currently set in the underlying * map. * * @param key Object whose count is incremented by <code>1</code> */ public void increment(E key) { increment(key,1); } /** * Increment the value of the specified key by the specified * amount. Sets the value of the key to the specified increment * amount if it is not currently set in the underlying map. If * the value after incrementing is <code>0</code>, the key is * removed from the map. * * @param key Object whose count is incremented by the specified * amount. * @param n Amount to increment the object by. */ public void increment(E key, int n) { if (!containsKey(key)) { put(key,new Counter(n)); return; } Counter counter = (Counter) get(key); counter.increment(n); if (counter.value() == 0) remove(key); } /** * Sets the value of the specified key to be the specified amount. * If the amount is <code>0</code>, the key is removed from the mapping. * * @param key Object whose count is incremented by the specified * amount. * @param n Amount to increment the object by. */ public void set(E key, int n) { if (n == 0) { remove(key); return; } if (!containsKey(key)) { put(key,new Counter(n)); return; } Counter counter = get(key); counter.set(n); } /** * Returns the current count value for the specified key. * If the key is not in the underlying map, the value * returned is <code>0</code>. * * @return Current value of count for the key. */ public int getCount(E key) { if (!containsKey(key)) return 0; return get(key).value(); } /** * Returns a string representation of this map. * * @return String representation of this map. */ public String toString() { StringBuffer sb = new StringBuffer(); List<E> keyList = keysOrderedByCountList(); for (E key : keyList) { sb.append(key); sb.append('='); sb.append(getCount(key)); sb.append('\n'); } return sb.toString(); } /** * Returns a list of keys for this object to counter map sorted * in descending order of count. Modifying the resulting list * does not affect this counter. * * @return List of keys for this object to counter map sorted * in descending order of count. */ public List<E> keysOrderedByCountList() { Set<E> keySet = keySet(); List<E> result = new ArrayList<E>(keySet().size()); result.addAll(keySet); Collections.sort(result,countComparator()); return result; } /** * Returns the array of keys for this object to counter * map sorted in decreasing order of their value counts. * * @return The array of keys for this counter ordered in * descending order of count. */ public Object[] keysOrderedByCount() { return keysOrderedByCountList().toArray(); } /** * Removes all entries in this counter that have less than * the specified minimum count. * * @param minCount Minimum count of objects to retain. */ public void prune(int minCount) { Iterator<Map.Entry<E,Counter>> it = entrySet().iterator(); while (it.hasNext()) if (it.next().getValue().value() < minCount) it.remove(); // remove this entry } /** * Returns a <code>CountComparator</code> that compares objects * based on their counts in this object to counter map. It first * compares objects based on their count, and if the counts are * the same and the objects are comparable, on the objects * themselves. Thus <code>compare(obj1,obj2)</code> method will * not be <i>consistent with equals</i> (see {@link Comparable}) * unless the set of keys has a natural ordering that is * consistent with <code>equals</code>. This inconsistency with * <code>equals</code> is tolerable in cases where the comparator * is used for sorting, as in {@link * java.util.Arrays#sort(Object[],Comparator)}, but not for * backing a sorted collection such as {@link java.util.TreeMap} * or {@link java.util.TreeSet}. * * @return Comparator based on this object to counter map's * counts. */ public Comparator<E> countComparator() { return new Comparator<E>() { public int compare(E o1, E o2) { int count1 = getCount(o1); int count2 = getCount(o2); if (count1 < count2) return 1; if (count1 > count2) return -1; if (!(o1 instanceof Comparable) || !(o2 instanceof Comparable)) return 0; Comparable c1 = (Comparable) o1; Comparable c2 = (Comparable) o2; return c1.compareTo(c2); } }; }}
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -