test.c

来自「可模拟实现Linux用户级线程库的静态调用,规避了多线程库的竞态条件和复杂的同步」· C语言 代码 · 共 93 行

/*学号：200620110268
  姓名：李海波*/

#include "uthread.c"

void f(int l)
{
	int k = 0,i;
	for (i=0;i<4;i++) {
	    k += l;
	    printf("in f (%d)\n", k);
	    usleep(SECOND);
	}
	uthreads_exit();
}

void g(int l)
{	
	int k = 0,i;
	for (i=0;i<8;i++) {
	    k += l;
	    printf("in g (%d)\n", k);
	    usleep(SECOND);
	}
uthreads_exit();

}



void h(int l)
{
	int k = 0,i;
	for (i=0;i<7;i++) {
	    k += l;
	    printf("in h (%d)\n", k);
	    usleep(SECOND);
	}
uthreads_exit();
}

void y(int l)
{
	int k = 0,i;
	for (i=0;i<8;i++) {
	    k += l;
	    printf("in y (%d)\n", k);
	    usleep(SECOND);
	}
	uthreads_exit();
}



int main()
{
	int err;
	long tid;


	printf("  Test libuthread begin:\n");
	if((err = uthreads_init()) == -1)
	uthreads_perror("in uthread_init.\n");

	printf("  Create a thread.\n");
	if((err = uthreads_spawn(4096, f, 1)) == -1)	
	uthreads_perror("in uthread_spawn\n");

	printf("  Create a thread.\n");
	if((err = uthreads_spawn(4096,g, 2)) == -1)
	uthreads_perror("in uthread_spawn\n");

	printf("  Create a thread.\n");
	if((err = uthreads_spawn(4096, h, 3)) == -1)
	uthreads_perror("in uthread_spawn\n");
	
	printf("  Create a thread.\n");
	if((err = uthreads_spawn(4096, y, 4)) == -1)
	uthreads_perror("in uthread_spawn\n");



printf("当前活跃的进程为%d个\n",total_thread_num);
		printf("\n");
	printf("  Start threads.\n");
	err = uthreads_start();


	printf("YEACH,测试成功!\n");

	return 0;
}