fac3_10_1.java
来自「java 算法设计与分析的好资料.由王晓东先生主编.」· Java 代码 · 共 49 行
JAVA
49 行
//本程序取自王晓东编著“算法分析与设计”第 100 页,例
//最优二叉搜索树问题动态规划改进解法
public class Fac3_10_1{
public static void obst(float a[],float b[],float [][]m,int [][]s,float[][] w)
{
int n=a.length-1;
for(int i=0;i<=n;i++){
w[i+1][i]=a[i];
m[i+1][i]=0;
s[i+1][i]=0;
}
for(int r=0;r<n;r++)
for(int i=1;i<=n-r;i++){
int j=i+r;
int i1=s[i][j-1]>i? s[i][j-1]:i;
int j1=s[i+1][j]>i? s[i+1][j]:j;
w[i][j]=w[i][j-1]+a[j]+b[j];
m[i][j]=m[i][i1-1]+m[i1+1][j];
s[i][j]=i1;
for(int k=i1+1;k<=j1;k++){
float t=m[i][k-1]+m[k+1][j];
if(t<=m[i][j]){
m[i][j]=t;
s[i][j]=k;
}
}
m[i][j]+=w[i][j];
}
}
public static void main(String args[])
{
float a1[]={0.06f,0.03f,0.05f,0.04f,0.06f,0.1f};
float b1[]={0.0f,0.2f,0.2f,0.06f,0.1f,0.1f};
int n1=a1.length;
int n2=b1.length;
float m1[][]=new float[n1+1][n2+1] ;
int s1[][]=new int[n1+1][n2+1];
float [][]w1=new float[n1+1][n2+1];
obst(a1,b1,m1,s1,w1);
System.out.println("输出二叉最优搜索树根结点元素 ");
for(int i=1;i<n1;i++){
for(int j=1;j<n2;j++)
System.out.print(s1[i][j]+" ");
System.out.println();
}
}
}
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